从源目录运行时，“flask run”找不到代码，而“python -m flask run”成功

Question

This is not the same as "What is the purpose of the -m switch" as I'm talking about a function that runs independently (flask) and wanting to know why it works differently with -m. The answers there do not resolve the question.

I have a flask app that I'm building. It's set up with a subdirectory for the code, so

setup.py
gallery/
   __init.py__
   models.py
   view.py

When I run it using 'python -m flask run' it works. When I run it just as 'flask run' it doesn't. I haven't been able to find anyone who knows what the actual difference is between the two commands, so I'm kind of stuck.

Here's the output from 'flask run':

(venv)MacBook-Pro-4:Finished khunter$ export FLASK_APP=gallery
(venv)MacBook-Pro-4:Finished khunter$ flask run
Usage: flask run [OPTIONS]

Error: The file/path provided (gallery) does not appear to exist.  Please      
verify the path is correct.  If app is not on PYTHONPATH, ensure the 
extension is .py

Any thoughts about where the difference lies so I can use 'flask run' appropriately?

EDIT: It looks like I can get through this with pip install --editable to grab the setup.py I have there.

Answer 1

There isn't many differences. When you run python -m flask run , you are running flask/__main__.py .

While when you run flask run , you are running flask/cli.py .

As you can see, the first one is just an alias of the second one. Although it passes as_module == True . The reason why it need to be additionally processed is showed in comment. You can check it by yourself.

I believe your issue is caused by path problem. Double check if your path is correct.