[英]Nested ifelse statement in a for loop
I am trying a nested ifelse statement within a for loop to create a new variable, the values of which are based on the frequency of occurrence of a factor variable (a list of postcodes). 我正在尝试在for循环中使用嵌套的ifelse语句来创建一个新变量,其值基于因子变量(邮政编码列表)的出现频率。
The new variable should return a predefined series of numbers based on the frequency of a postcode (frequencies range between 1 and 4). 新变量应根据邮政编码的频率(频率范围在1到4之间)返回预定义的一系列数字。 Each of these number series must end in 800 and increase in increments of 200, the starting point of which depends on the frequency of each postcode: the higher the frequency, the lower the starting increment of 200.
这些数字系列中的每一个必须以800结尾,并以200为增量增加,其起始点取决于每个邮政编码的频率:频率越高,起始增量200越低。
For this I have defined a for loop, in which I first measure the frequency of each postcode, followed by a nested ifelse statement, specifying each series of numbers to be allocated to the NewVar based on the frequency. 为此,我定义了一个for循环,在该循环中,我首先测量每个邮政编码的频率,然后嵌套一个ifelse语句,根据频率指定要分配给NewVar的每个数字序列。
A small intuitive example of what I want to achieve is written here, I want to apply this on a dataframe containing millions of postcodes. 这里写了一个我想要实现的直观小示例,我想将此示例应用于包含数百万个邮政编码的数据框。
DESIRED RESULT: 所需结果:
Postcode NewVar
AA 600
AA 800
BB 400
BB 600
BB 800
CC 800
DD 200
DD 400
DD 600
DD 800
CODE: 码:
DF$NewVar <- 0
DF$NewVar <- for (i in levels(DF$Postcode[i]))
ifelse((table(DF$Postcode[i]) == 4), DF$NewVar[i] <- c(200,400,600,800),
(ifelse ((table(DF$Postcode[i]) == 3), DF$NewVar[i] <- c(400,600,800),
(ifelse ((table(DF$Postcode[i]) == 2), DF$NewVar[i] <- c(600,800),
DF$NewVar[i] <- c(800))))))
PROBLEM 1: 问题1:
Firstly, when running the entire code, I receive an error stating that there is a mismatch between the amount of rows in the replacement versus the data, whilst when manually checking for this, it is not the case (the mismatch is always limited to exactly 1 row). 首先,在运行整个代码时,我收到一条错误消息,指出替换中的行数与数据之间存在不匹配,而在手动检查时,情况并非如此(不匹配始终限于完全匹配1行)。
Error in `$<-.data.frame`(`*tmp*`, NewVar, value = c("0", "0", "0", :
replacement has 11 rows, data has 10.
PROBLEM 2: 问题2:
TESTING IF AN IFELSE WORKS ON ITS OWN (OUT OF THE LOOP): 如果无法进行自己的工作,请进行以下测试:
When verifying if the ifelse clause works on its own (outside of the loop), I see that only the starting increment of 200 is copied on each line of NewVar, so it does not increment to 800. This is not what I want to achieve either: 当验证ifelse子句是否可以单独工作时(在循环外部),我看到NewVar的每一行仅复制了200的开始增量,因此它不会增加到800。这不是我想要实现的目标之一:
CODE TESTING ONE IFELSE: 一项代码测试:
DF$NewVar[1:2] <- ifelse((sum(table(DF$Postcode)) == 2),
DF$NewVar[1:2] <- c(600,800), "NA")
RESULT (not desired): 结果(不期望):
Postcode NewVar
AA 200
AA 200
DESIRED RESULT: 所需结果:
Postcode NewVar
AA 200
AA 400
Note: I predefined the NewVar column before trying to allocated the variable, and I have checked for NA´s already as well. 注意:在尝试分配变量之前,我预定义了NewVar列,并且我也已经检查了NA。
Thank you in advance for your time. 预先感谢您的宝贵时间。
One way if you're willing to use dplyr : 如果您愿意使用dplyr的一种方法:
library(dplyr)
DF <- structure(list(Postcode = c("AA", "AA", "BB", "BB", "BB", "CC",
"DD", "DD", "DD", "DD")), class = "data.frame", row.names = c(NA,
-10L))
vals <- c(200,400,600,800)
DF %>% group_by(Postcode) %>% mutate(NewVar = tail(vals,n()))
For the sake of completeness, here is a base R solution which uses the ave()
function. 为了完整起见,这是使用
ave()
函数的基本R解决方案。
Let's assume Postcode
is a vector of postcodes in random order: 假设
Postcode
是随机顺序的邮政编码向量 :
Postcode
[1] "BB" "CC" "CC" "BB" "BB" "AA" "CC" "BB" "AA" "DD"
the code below creates a data.frame including Postcode
and NewVar
: 下面的代码创建一个data.frame,其中包括
Postcode
和NewVar
:
data.frame(
Postcode,
NewVar = ave(Postcode, Postcode,
FUN = function(x) seq(to = 800, by = 200, length.out = length(x)))
)
Postcode NewVar 1 BB 200 2 CC 400 3 CC 600 4 BB 400 5 BB 600 6 AA 600 7 CC 800 8 BB 800 9 AA 800 10 DD 800
# create data
library(magrittr) # only used to improve readability
n_codes <- 4L
set.seed(1L)
Postcode <-
stringr::str_dup(LETTERS[1:n_codes], 2L) %>% # create codes
rep(times = sample(n_codes)) %>% # replicate randomly
sample() # re-order randomly
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