简体   繁体   English

计算直方图的最小值和最大值

[英]Calculating minimum and maximum values of a histogram

I have an image that is grayscale (has a single band) with values ranging from -182 to 94. However, for the most part, the histogram of the image occupies just a narrow range as shown in the diagram below. 我有一幅灰度图像(具有单个波段),其值介于-182到94之间。但是,在大多数情况下,图像的直方图仅占很小的范围,如下图所示。 I have the values of the pixels in an array. 我有一个数组中的像素值。 I want to find the start and end of the histogram (in this case around 22 to 70). 我想找到直方图的起点和终点(在这种情况下,约为22到70)。 Is there any built in function that I can use to do that? 我可以使用任何内置函数吗? I am using C#, Emgu CV and GDAL 我正在使用C#,Emgu CV和GDAL

在此处输入图片说明

If I understand correctly, you can pixels as an sbyte array, in which case this works for me: 如果我理解正确,则可以将像素作为sbyte数组,在这种情况下,这对我有用:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleMinMax
{
    class Program
    {
        static void Main(string[] args)
        {
            sbyte[] array1 = { 1, -1, -2, 0, 99, -111 };

            MinMax(array1);

            void MinMax(sbyte[] array)
            {
                // Report minimum and maximum values.
                Console.WriteLine("max = {0}; min = {1}", array.Max(), array.Min());
            }
        }
    }
}

Assuming your histogram values are in an int[] called hist , you can use some LINQ extension methods to find the largest contiguous group of values, and find their start and end positions in the array. 假设直方图值位于称为histint[] ,则可以使用某些LINQ扩展方法来找到最大的连续值组,并在数组中找到它们的开始和结束位置。 This is overkill if your histogram simply has all zeros with one non-zero area, and does not handle multiple non-zero areas very well - it just picks the longest horizontal span. 如果您的直方图仅具有一个非零区域的全零,并且不能很好地处理多个非零区域,那就太过分了-它只选择最长的水平跨度。

var histPos = hist
                .Select((hval, pos) => new { hval, pos })
                .GroupByWhile((prev,cur) => prev.hval != 0 && cur.hval != 0)
                .MaxBy(zvg => zvg.Count())
                .Select(zvg => zvg.pos);
var start = histPos.Min();
var end = histPos.Max();

The extension methods I used are GroupByWhile which groups sequential objects as long as a boolean lambda returns true, and MaxBy which returns the object that has the largest return value from a lambda. 我使用的扩展方法是GroupByWhile ,它对布尔对象lambda返回true的对象进行组合,而MaxBy从lambda返回具有最大返回值的对象。

public static class IEnumerableExt {
    // TKey combineFn((TKey Key, T Value) PrevKeyItem, T curItem):
    // PrevKeyItem.Key = Previous Key
    // PrevKeyItem.Value = Previous Item
    // curItem = Current Item
    // returns new Key
    public static IEnumerable<(TKey Key, T Value)> ScanPair<T, TKey>(this IEnumerable<T> src, TKey seedKey, Func<(TKey Key, T Value), T, TKey> combineFn) {
        using (var srce = src.GetEnumerator()) {
            if (srce.MoveNext()) {
                var prevkv = (seedKey, srce.Current);

                while (srce.MoveNext()) {
                    yield return prevkv;
                    prevkv = (combineFn(prevkv, srce.Current), srce.Current);
                }
                yield return prevkv;
            }
        }
    }

        // bool testFn(T prevItem, T curItem)
    // returns groups by sequential matching bool
    public static IEnumerable<IGrouping<int, T>> GroupByWhile<T>(this IEnumerable<T> src, Func<T, T, bool> testFn) =>
        src.ScanPair(1, (kvp, cur) => testFn(kvp.Value, cur) ? kvp.Key : kvp.Key + 1)
           .GroupBy(kvp => kvp.Key, kvp => kvp.Value);

    public static T MaxBy<T, TKey>(this IEnumerable<T> src, Func<T, TKey> keySelector, Comparer<TKey> keyComparer) => src.Aggregate((a, b) => keyComparer.Compare(keySelector(a), keySelector(b)) > 0 ? a : b);
    public static T MaxBy<T, TKey>(this IEnumerable<T> src, Func<T, TKey> keySelector) => src.Aggregate((a, b) => Comparer<TKey>.Default.Compare(keySelector(a), keySelector(b)) > 0 ? a : b);    
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM