如何正确导入适用于 Python 3.6 的 Azure SDK

Question

I am creating a flask app that can upload files to my azure blob.我正在创建一个烧瓶应用程序，可以将文件上传到我的 azure blob。 When I test the code locally on my python virtualenv, the app works perfectly.当我在 python virtualenv 上本地测试代码时，该应用程序运行良好。 When I create a docker container and push the image to Azure App services, container log shows below error:当我创建一个 docker 容器并将图像推送到 Azure App 服务时，容器日志显示以下错误：

2019-01-12T08:02:55.541803195Z Python version: 3.6.5 (default, Aug 22 2018, 14:20:40)  [GCC 6.4.0]
2019-01-12T08:02:55.593272447Z *** Python threads support is disabled. You can enable it with --enable-threads ***
2019-01-12T08:02:55.604159596Z Python main interpreter initialized at 0x557d000b7f40
2019-01-12T08:02:55.604196797Z uWSGI running as root, you can use --uid/--gid/--chroot options
2019-01-12T08:02:55.604302601Z *** WARNING: you are running uWSGI as root !!! (use the --uid flag) *** 
2019-01-12T08:02:55.604306901Z your server socket listen backlog is limited to 100 connections
2019-01-12T08:02:55.604310901Z your mercy for graceful operations on workers is 60 seconds
2019-01-12T08:02:55.604314901Z mapped 1239640 bytes (1210 KB) for 16 cores
2019-01-12T08:02:55.604318801Z *** Operational MODE: preforking ***
2019-01-12T08:02:56.273272972Z Traceback (most recent call last):
2019-01-12T08:02:56.273720386Z   File "./main.py", line 4, in <module>
2019-01-12T08:02:56.274117299Z     from azure.storage.blob import BlockBlobService
2019-01-12T08:02:56.274378307Z ModuleNotFoundError: No module named 'azure'
2019-01-12T08:02:56.274618915Z unable to load app 0 (mountpoint='') (callable not found or import error)
2019-01-12T08:02:56.274863423Z *** no app loaded. GAME OVER ***

I have tried multiple solutions mentioned on Github issues and other similar stackoverflow queries.我已经尝试了 Github 问题和其他类似的 stackoverflow 查询中提到的多种解决方案。 The usual suggestions were to install azure-storage < 0.36, install azure==0.11.1 etc but none of them have solved my problem.通常的建议是安装 azure-storage < 0.36，安装 azure==0.11.1 等，但它们都没有解决我的问题。 https://github.com/Microsoft/AzureNotebooks/issues/460 https://github.com/Azure/azure-sdk-for-python/issues/3623 https://github.com/Microsoft/AzureNotebooks/issues/460 https://github.com/Azure/azure-sdk-for-python/issues/3623

#azure==0.11.1
#azure==2.0.0
click==6.7
Flask==0.12.2
itsdangerous==0.24
Jinja2==2.10
MarkupSafe==1.0
Werkzeug==0.14.1
#azure-common==1.1.3
#azure-nspkg==1.0.0
azure-storage==0.31.0
futures==3.0.5
python-dateutil==2.5.3
requests>=2.20.0
six==1.10.0

Can anyone help me understand the cause of this issue.谁能帮我理解这个问题的原因。

Edit: Adding my code for as requested in one of the comments:编辑：根据评论之一的要求添加我的代码：

import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename
from azure.storage.blob import BlockBlobService
from azure.storage import CloudStorageAccount
from azure.storage.blob import ContentSettings
import string, random, requests
import traceback
import mimetypes

app = Flask(__name__, instance_relative_config=True)
account = 'fileupoader'   # Azure account name
key = 'some_key' # Azure Storage account access key 
container = 'files' 
blob_service = BlockBlobService(account_name=account, account_key=key)
#print (blob_service)

@app.route('/', methods=['GET', 'POST'])
def upload_file():
        if request.method == 'POST':
            f = request.files['file']
            mime_type = f.content_type
            print (mime_type)
            #print (type(f))
            try:
                blob_service.create_blob_from_stream(container, f.filename, f,
                content_settings=ContentSettings(content_type=mime_type))
            except Exception as e:
                print (str(e))
                pass
            ref =  'https://'+ account + '.dfs.core.windows.net/' + container + '/' + f.filename
            print (ref)
            return '''
            <!doctype html>
            <title>File Link</title>
            <h1>Uploaded File Link</h1>
            <p>''' + ref + '''</p>
            <img src="'''+ ref +'''">
            '''
        return '''
        <!doctype html>
        <title>Upload new File</title>
        <h1>Upload new File</h1>
        <form action="" method=post enctype=multipart/form-data>
            <p><input type=file name=file>
                    <input type=submit value=Upload>
        </form>
        '''

def id_generator(size=32, chars=string.ascii_uppercase + string.digits):
        return ''.join(random.choice(chars) for _ in range(size))

if __name__ == '__main__':
        app.run(debug=True)

Answer 1

azure-storage is deprecated, do not use it but the specific version like these three: azure-storage已弃用，请勿使用它，而是使用以下三个特定版本：

Do not use azure as well, since it's just a meta-package that brings other and don't contain code.也不要使用azure ，因为它只是一个带有其他的元包，不包含代码。 There is no value to use it if you use directly service specific package like azure-storage-queue (which is the recommendation)如果您直接使用特定于服务的包，如azure-storage-queue （这是推荐的），则没有使用它的价值

(I work at MS in the SDK team) （我在 MS 的 SDK 团队工作）

如何正确导入适用于 Python 3.6 的 Azure SDK

问题描述

1 个解决方案

解决方案1
2 已采纳 2019-01-12 17:53:05

如何正确导入适用于 Python 3.6 的 Azure SDK

问题描述

1 个解决方案

解决方案1 2 已采纳 2019-01-12 17:53:05

解决方案1
2 已采纳 2019-01-12 17:53:05