在 python 中执行 grep -v 的更快方法

Question

i have two list , a = ["1","3","4","22","2"] and b = ["1","2"]

is there a way to get the output c = ["3","4"] in python, just like

grep -vf b a

in bash if you have file a

1
3
4
22
2

and b

1
2

i cannot using grep , and i tried this , but it takes a long time if the list is big , is there a way to do it faster in python ?

c = []
d = []

for i in b:
    for j in a:
        if i in j:
                d.append(j)       
c = list(set(a).difference(d))

is there a way to do it faster in python ?

Answer 1

One way using list-comprehension :

c = [i for i in a if not any(j in b for j in i)]
print (c)
#['3', '4']