[英]Combining observables of array objects
How do you combine two or more observable of array ie Observable<Object[]>, Observable<Object[]>
using rxjs in order to return one Observable<Object[]>
?您如何使用 rxjs 组合两个或多个可观察的数组,即
Observable<Object[]>, Observable<Object[]>
以返回一个Observable<Object[]>
?
forkJoin
and merge
are emitting the two Observable<Object[]>
arrays independently. forkJoin
和merge
分别发出两个Observable<Object[]>
数组。
getEmployeesLeavesByEmployeeNumber2(employeeNumber,afromDate,atoDate) {
const scenario1 = this.afs.collection(`${environment.FB_LEAVES}`, ref => {
let query: firebase.firestore.CollectionReference | firebase.firestore.Query = ref;
query = query.where("employeeNumber", "==", employeeNumber);
query = query.where("fromDate",">=",afromDate);
query = query.where("fromDate","<=",atoDate);
return query;
}).snapshotChanges()
.pipe(take(1))
.pipe(
map(changes => {
return changes.map(a => {
const data = a.payload.doc.data() as Leave;
data.docId = a.payload.doc.id;
return data;
})
})
).pipe(map(leaves => {
let leavesArr=leaves.filter(leave => leave.status!==environment.LEAVE_STATUS_DECLINED)
return leavesArr;
}));
const scenario2 = this.afs.collection(`${environment.FB_LEAVES}`, ref => {
let query: firebase.firestore.CollectionReference | firebase.firestore.Query = ref;
query = query.where("employeeNumber", "==", employeeNumber);
query = query.where("toDate","<=",afromDate);
query = query.where("toDate","<=",atoDate);
return query;
}).snapshotChanges()
.pipe(take(1))
.pipe(
map(changes => {
return changes.map(a => {
const data = a.payload.doc.data() as Leave;
data.docId = a.payload.doc.id;
return data;
})
})
).pipe(map(leaves => {
let leavesArr=leaves.filter(leave => leave.status!==environment.LEAVE_STATUS_DECLINED)
return leavesArr;
}));
const scenario3 = this.afs.collection(`${environment.FB_LEAVES}`, ref => {
let query: firebase.firestore.CollectionReference | firebase.firestore.Query = ref;
query = query.where("employeeNumber", "==", employeeNumber);
query = query.where("fromDate","<=",afromDate);
return query;
}).snapshotChanges()
.pipe(take(1))
.pipe(
map(changes => {
return changes.map(a => {
const data = a.payload.doc.data() as Leave;
data.docId = a.payload.doc.id;
return data;
})
})
).pipe(
filter(leave => {
return leave!==undefined;
})
);
return merge(scenario1,scenario2);
}
I am expecting a single observable of array but getting 2 ie我期待一个单一的可观察数组,但得到 2 ie
emp's leaves: [{…}]
assign.component.ts:198 leaves array length at assignment error 1
assign.component.ts:168 emp's leaves: (2) [{…}, {…}]
assign.component.ts:198 leaves array length at assignment error 2
我已经使用它来工作:
return forkJoin(scenario1,scenario2).pipe(map((arr) => [...arr[0],...arr[1]] ));
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