为什么从绑定函数返回的`this`不能严格等于传递的原始值？

Question

I noticed that this returned from bound function doesn't strictly equal primitive value passed when binding.

According to MDN when the original function is called [[BoundThis]] gets passed.

What is this returned from bound function? Is it [[BoundThis]] ?

const fn = function() { return this }
const strBound = fn.bind('111')
const numBound = fn.bind(111)
const boolBound = fn.bind(true)

console.log(strBound()) // [String: '111']
console.log(strBound() == '111') // true
console.log(strBound() === '111') // false

console.log(numBound()) // [Number: 111]
console.log(numBound() == 111) // true
console.log(numBound() === 111) // false

console.log(boolBound()) // [Boolean: true]
console.log(boolBound() == true) // true
console.log(boolBound() === true) // false

Answer 1

Your function is not in strict mode, which means it will always implicitly cast its received this value to an object (and uses the global object upon receiving null / undefined ). Your code will work as expected with

function fn() {
    "use strict";
    return this;
}

Notice that one could reproduce the issue without bind .

Answer 2

This behaviour, as always, has been defined by the ECMAScript specification. In this case it takes a while to actually follow the different specifications, but if you are interested in the details, here you go.

19.2.3.2 Function.prototype.bind ( thisArg , ...args)

[...]

4. Let F be BoundFunctionCreate (Target, thisArg, args).

[...]

16. Return F.

---

9.4.1.3 BoundFunctionCreate (targetFunction, boundThis, boundArgs)

[...]

6. Set the [[Call]] internal method of obj as described in 9.4.1.1.

---

9.4.1.1 [[Call]] ( thisArgument, argumentsList)

[...]

5. Return Call (target, boundThis, args).

---

7.3.12 Call(F, V, [argumentsList])

[...]

4. Return F. [[Call]] (V, argumentsList).

---

9.2.1 [[Call]] ( thisArgument, argumentsList)

[...]

6. Perform OrdinaryCallBindThis (F, calleeContext, thisArgument).

---

9.2.1.2 OrdinaryCallBindThis ( F, calleeContext, thisArgument )

[...]

5. If thisMode is strict, let thisValue be thisArgument.
6. Else
   • if thisArgument is null or undefined, then
     Let thisValue be calleeRealm.[[globalThis]].
   • Else
     Let thisValue be ToObject (thisArgument).

---

7.1.13 ToObject ( argument )

[...]

Number: Return a new Number object whose [[NumberData]] internal slot is set to the value of argument. See 20.1 for a description of Number objects.

String: Return a new String object whose [[StringData]] internal slot is set to the value of argument. See 21.1 for a description of String objects.

• A primitive string is not strictly equal to a string object with the same value.
• A primitive number is not strictly equal to a number object with the same value.

Answer 3

Binding a function to a string primitive implicitly converts the string primitive into a String object.

When type coercion is in play, a string primitive and String object will match.

Without type coercion, they won't.

Ditto other kinds of primitives.

 const prim = "x"; const obj = new String("x"); console.log(prim instanceof String); console.log(obj instanceof String); console.log(prim == obj); console.log(prim === obj);