[英]PHP Regex pattern to get a specify word
i have some strings result of var_dump
like this : 我有一些类似
var_dump
字符串结果:
string(5) "tes37"
string(6) "SRV410"
string(6) "SRV400"
string(6) "SRV311"
string(6) "SRV302"
string(6) "SRV301"
string(6) "SRV300"
string(6) "SRV001"
string(7) "SRV_123"
string(5) "sad34"
string(7) "S 0001J"
string(8) "S 00004J"
string(8) "S 00003J"
string(8) "S 00002J"
string(6) "asdasd"
string(4) "4356"
string(3) "234"
here i want to get string with regex such as : S 0001J, S 00002J, S 00003J and S00004J 在这里我想用正则表达式获取字符串,例如:S 0001J,S 00002J,S 00003J和S00004J
anyone can help me out to make the pattern regex ? 任何人都可以帮助我制作正则表达式吗? Thank you
谢谢
If you don't care about the number of zeros in the string, you can use the following regex: 如果您不关心字符串中的零个数,则可以使用以下正则表达式:
S 0+[1-9]J
Change the +
to a quantifier of the form {number, number}
if you want to keep the number of zeros within a specific number. 如果要将零数保持在特定数字内
{number, number}
请将+
更改为{number, number}
形式的量词。 For example, if you want between three to five zeros, you can do S 0{3,5}[1-9]J
. 例如,如果要在三到五个零之间,则可以执行
S 0{3,5}[1-9]J
Of course, this is assuming the string is following the format S (a number of zeros)(a digit)J
当然,这是假设字符串遵循格式
S (a number of zeros)(a digit)J
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