AngularJS检查条件并返回true或false

Question

I have html like this :

<td><span ng-if="isuser(user) == false" type="button" >not allowed</span> </td>

the above html is displayed only if the function isuser(user) return false.

I have an array like this :

$scope.list = ["456", "111", "459"];

Now the user object has an array called id . This id array contains a number key whose value can be 456 , 111 or 459 and sometimes it may be empty also.

The user object :

{"name":"pravin","status":"Live","id":[{"number":"111"}],"msg":"test"}

Here is the isuser function :

$scope.isuser = function(user) {
  for (var i = 0; i < $scope.list.length; i++){
  var exists = user.id.find(({number}) => number === $scope.list[i]);
  }
if (exists)
  return true;
else
  return false;
};

but this always returns false.

I want the for loop to check if none of the values of the number key exists in the list array and then only return false. How do I do it?

Answer 1

The issue is that the below statement

var exists = user.id.find(({number}) => number === $scope.list[i]);

updates every time the exists variable and always you'll get the last change.

One approach could be using some method by passing a callback function as argument.

$scope.isuser = function(user) {
   var exists = user.id.some(({number}) => $scope.list.includes(number));
   return exists;
}

Answer 2

Try this it will help you

  $scope.isuser = function(user) {
       var exists = false;
    for (var i = 0; i < $scope.list.length; i++){
      exists = user.id.find(({number}) => number === $scope.list[i]);
    }
     if(i==$scope.list.length-1){
      if (exists)
        return true;
      else
        return false;
      }
  loop };