json.load痛苦创建字典而不是列表

Question

I have a python script which grabs data from a site in json:

channels_json = json.loads(url)

the site returns data as follows:

[ { '1': 'http://ht.co/bbda24210d7bgfbbbbcdfc2a023f' },
{ '2': 'http://ht.co/bbd10d7937932965369c248f7ccdfc2a023f' },
{ '3': 'http://ht.co/d3a01f6e5e74eb2cb5840556d80a52adf2871d' },
{ '4': 'http://ht.co/56d3a01f6e5e72cb5840556d80a52adf2871d' },
{ '5': 'http://ht.co/9ed0bb4cc447b99c9ce609916ccf931f16a' },
{ '6': 'http://ht.co/9ed0bb4cc44bb99c9ce609916ccf931f16a' },
....]

The problem is that Python is making this into a list rather than a dictionary. So I can't reference '4' like this:

print (channels_json["4"])

and get the response:

http://ht.co/56d3a01f6e5e72cb5840556d80a52adf2871d    

Instead Python spits out:

TypeError: list indices must be integers, not str

If I run this code:

for c in channels_json:
   print c

Python prints out each set of coupled data like this:

{u'1': u'http://ht.co/bbda24210d7bgfbbbbcdfc2a023f' },
{ u'2': u'http://ht.co/bbd10d7937932965369c248f7ccdfc2a023f' },
{ u'3': u'http://ht.co/d3a01f6e5e74eb2cb5840556d80a52adf2871d' },
{ u'4': u'http://ht.co/56d3a01f6e5e72cb5840556d80a52adf2871d' },
{ u'5': u'http://ht.co/9ed0bb4cc447b99c9ce609916ccf931f16a' },
{ u'6': u'http://ht.co/9ed0bb4cc44bb99c9ce609916ccf931f16a' },

How can I get the above into a dictionary so I can reference value '6' as a string and get back

http://ht.co/9ed0bb4cc44bb99c9ce609916ccf931f16a

Answer 1

You can create the dictionary you want by iterating over the dictionaries in the list returned from json.load() as shown below:

#json_data = json.loads(url)

json_data = [{ '1': 'http://ht.co/bbda24210d7bgfbbbbcdfc2a023f' },
             { '2': 'http://ht.co/bbd10d7937932965369c248f7ccdfc2a023f' },
             { '3': 'http://ht.co/d3a01f6e5e74eb2cb5840556d80a52adf2871d' },
             { '4': 'http://ht.co/56d3a01f6e5e72cb5840556d80a52adf2871d' },
             { '5': 'http://ht.co/9ed0bb4cc447b99c9ce609916ccf931f16a' },
             { '6': 'http://ht.co/9ed0bb4cc44bb99c9ce609916ccf931f16a' },]

# Convert to single dictionary.    
channels_json = dict(d.popitem() for d in json_data)

print(json.dumps(channels_json, indent=4))  # Pretty-print result.

Output:

{
    "1": "http://ht.co/bbda24210d7bgfbbbbcdfc2a023f",
    "2": "http://ht.co/bbd10d7937932965369c248f7ccdfc2a023f",
    "3": "http://ht.co/d3a01f6e5e74eb2cb5840556d80a52adf2871d",
    "4": "http://ht.co/56d3a01f6e5e72cb5840556d80a52adf2871d",
    "5": "http://ht.co/9ed0bb4cc447b99c9ce609916ccf931f16a",
    "6": "http://ht.co/9ed0bb4cc44bb99c9ce609916ccf931f16a"
}

Answer 2

 dd = {}

 for d in c:
     for key, value in d.items():
         dd[key] = value

Answer 3

You can just iterate through the array and build your dictionary

channels_json = {}
channels_array = json.loads(url)
for d in channels_array:
    key = list(d.keys())[0]
    val = d[key]
    channels_json[key] = val

Now you should be able to reference your dictionary channels_json

Answer 4

More pythonic way of doing this.

channels = {}
for i in json.loads(url): channels.update(i)

or

channels = {}
[channels.update(i) for i in json.loads(url)]

In both cases the dictionary gets updated with your list of separate dictionaries.