Jest - 模拟一个函数，该函数又定义了一个方法

Question

I am converting some old tests to use Jest, and I have a function that is called Services.Transactions.get . Normally you pass it a callback to process the data returned from a remote API. In my tests I'm mocking it, using

jest.spyOn(Services.Transactions, 'get').mockImplementation((callback) => { callback(someJsObject); });

So far so good.

Now the problem is that it in turn has a method Services.Transactions.get.watch . The module I'm testing uses both of these functions. Once I mock the first above, I can't mock the watcher method. I'm told Services.Transactions.get.watch is not a function.

I've tried:

• Defining a function with an empty watch method defined on it, and using it as the implementation for get.
• Trying to also replace the watch method using mockImplementation calls

None of the above worked. The file services is coming from is not an ES6 module so doing a module-level mock is something I'd prefer to avoid. Do I have any other options?

Answer 1

What about the straightforward approach:

const mock = jest.spyOn(Services.Transactions, 'get');
mock.watch = jest.fn();
mock.mockImplementation(...);