从MySql数据库的JSON列获取数据

Question

In my table there is a column with JSON encoded data and one record looks something like this

{"late_fee":10,
"due_date":"2019-10-01 00:00:00",
"property_type":"house"
}

When getting data from database I need records where key late_fee does not exist in JSON data column. How can I put it in where condition?

This is the line of code on which I have to add mentioned condition:

$payments = Rent::where('property_id', $property['id']);`

EDIT

By comments you posted, can you confirm me that this is the right way:

$payments = Rent::where('property_id', $property['id'])->whereJsonContains('notification_settings->late_fee', null);

PS notification_settings is the name of column where JSON data is stored.

Answer 1

Just read this short article: https://laravel.com/docs/5.7/queries#json-where-clauses

That should work :

$payments = Rent::where('property_id', $property['id'])->whereJsonContains('notification_settings->late_fee', null);