如何使用 MongoDB 聚合 $match 两个列表

Question

I have collection as: col1

{"_id":"5c3ea35651166f3refsfd5",
"environment": "production",
"application": ['cloud', 'android', 'finance']},

{"_id":"5c3ea35651166f3refsfd6",
"environment": "production",
"application": ['banking', 'network', 'finance']}

I want to project the data only if the application/s in collection matches with the application in the list of ['cloud', 'database', 'booking'] . In this case, I should be able to get only first document as it has ' cloud ' in both document as well as in list.

I need to use aggregation. But I am not getting correct direction..

Answer 1

You can use $in query operator

col1.aggregate([
  { '$match': { 'application': { '$in': ['cloud', 'database', 'booking'] }}},
  { '$project': { 'environment': 1, 'application':1 }}
])