如何在Cygwin中使用Python有效地将POSIX路径转换为Windows路径？

Question

Problem

Imagine you are writing a Python script which runs on cygwin and calls an external C# executable which requires as input a path. Assume you cannot change the C# executable in any way. As you send the path you want to the executable, it rejects all cygwin paths.

So if you pass the path /cygdrive/c/location/of/file.html as a POSIX path, it will fail as the executable requires a Windows path like C:\\location\\of\\file.html

Example:

Message location = os.path.dirname(os.path.realpath(__file__)) os.system('./cSharpScript.exe ' + message_location)

Will result in:

File for the content (/cygdrive/c/location/of/file.html) not found.

Things I've tried so far:

PATH = /cygdrive/c/location/of/file.html

1) path = PATH.replace('/','\\\\')

Result: File for the content (cygdriveclocationoffile.html) not found.

2) path = os.path.abspath(PATH)

Result: File for the content (/cygdrive/c/location/of/file.html) not found.

• os.path.realpath has the same results

I'm probably going in a completely wrong direction with my solutions so far... How would you handle it?

Answer 1

According to [Cygwin]: cygpath :

cygpath - Convert Unix and Windows format paths, or output system path information
...

 -w, --windows print Windows form of NAMEs (C:\\WINNT) 

Example:

 [cfati@cfati-5510-0:/cygdrive/e/Work/Dev/StackOverflow/q054237800]> cygpath.exe -w /cygdrive/c/location/of/file.html C:\\location\\of\\file.html 

Translated into Python ( this is a rough version, only for demonstrating purposes ):

 >>> import subprocess >>> >>> >>> def get_win_path(cyg_path): ... return subprocess.check_output(["cygpath", "-w", cyg_path]).strip(b"\\n").decode() ... >>> >>> print(get_win_path("/cygdrive/c/location/of/file.html")) C:\\location\\of\\file.html