用正则表达式提取单词，除非它是给定单词

Question

I am trying to match and extract part of an URL with regex, except if it is a given word.

Here is some test data which already works:

/api/add             --> no match
/api/add/view        --> no match
/api/user1           --> matches and extracts "user1"
/api/user1/profile/  --> matches and extracts "user1"

Not working:

/api/aaa/profile/  --> matches and extracts "aaa"

Here is the current regex I have:

/^\/api\/(?:([^\/(add)]+?))\/.*?$/i

I works as I want except if it contains "a" or "d" instead of the entire "add" word.

Answer 1

You may use this regex:

/^\/api\/(?!add(?:\/|$))([^\/]+)/i

RegEx Demo

In your regex when you use [^\\/(add)]+ that means any character except any of / . ( , a , d , ) characters because inside character class ie [...] there is no grouping.

Answer 2

如果您希望匹配“ / api / * / whatever”并返回为*找到的内容，除非它是“ add”

/^\/api\/(?!add\b)(\w+)(?:\/\w+)*\/?$/i