[英]mysql sum each row
query to get the results as below 查询以得到如下结果
table price( item int, amount int, quantity int, ) 表格价格(项目int,金额int,数量int,)
+-------+-------+----------+
| item | price | quantity |
+-------+-------+----------+
| box 1 | 1000 | 4 |
| box 2 | 2000 | 1 |
| box 3 | 3000 | 6 |
+-------+-------+----------+
result 结果
+-------+-------+----------+-----------+-------+
| item | price | quantity | sub total | total |
+-------+-------+----------+-----------+-------+
| box 1 | 1000 | 4 | 4000 | 16000 |
| box 2 | 2000 | 1 | 2000 | 18000 |
| box 3 | 3000 | 6 | 18000 | 36000 |
+-------+-------+----------+-----------+-------+
You can try below if your mysql version below 8.0 如果您的mysql版本低于8.0,可以尝试以下方法
select
item,price,quantity,price*quantity as total,
@totalall:= @totalall + price*quantity as TotalAll
from price, (Select @totalall:= 0) as totalall;
OR if your mysql vsersion 8.0+ then you can try below - 或者,如果您的MySQL vsersion 8.0+,则可以在下面尝试-
SELECT
item,price,quantity,price*quantity as total,
SUM(price*quantity) OVER(ORDER BY item) AS TotalAll
FROM price;
从交叉联接中选择数量,(@ sum:= @ sum +(item * amount))作为数量(选择@sum:= 0)参数
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