Hive 提取文本之前<br>

Question

In Apache hive how can i extract the substring from a given string. I have a column containing the below value.

I need to extract ABC3170 from the below string ie till <br>

my data looks some what like below. I want to get all the records and eliminate text after <BR>
Col1
---------
G3333
XYZD20
5289
ABC2620
CDF-B700S
CUSTOM MANAGER
ABC3170 <BR></DIV><DIV DIR="AUTO" STYLE="DIRECTION: LTR; MARGIN: 0; PADDING: 0; FONT-FAMILY: SANS-SE

Answer 1

Use Regexp_Extract function and matching java regex to extract the value before <BR>.

Regex Expression:

(.*?)\\s+<BR> //capture without space until <BR>

Hive Query:

hive> select regexp_extract(<column.name>,"(.*?)\\s+<BR>",1) from <db.name>.<tab.name>;

Example:

hive> select regexp_extract(txt,"(.*?)\\s+<BR>",1),txt from i;
+----------+---------------------------------------------------------------------------------------------------------------------------------------------+--+
|   _c0    |                                                                     txt                                                                     |
+----------+---------------------------------------------------------------------------------------------------------------------------------------------+--+
| ABC3170  | ABC3170 <BR></DIV><DIV DIR="AUTO" STYLE="DIRECTION: LTR; MARGIN: 0; PADDING: 0; FONT-FAMILY: SANS-SERIF; FONT-SIZE: 11PT; COLOR: BLACK; ">  |
+----------+---------------------------------------------------------------------------------------------------------------------------------------------+--+