URL匹配正则表达式模式

Question

I have a bunch of URLs that I need to filter out, based on whether it contains the keyword 'staff'

1. /services
2. /services/EarNoseThroat
3. /services/EarNoseThroat/Audiology
4. /services/EarNoseThroat/Audiology/CochlearImplant
5. /services/BehavioralHealth/Clinic  

6. /services/BehavioralHealth/Clinic/staff
7. /services/BehavioralHealth/Clinic/staff/Jamie-Hudgins

I want to create one regex pattern to match all the URLs that have /services after the host URL, but not 'staff' anywhere in the URL. Basically match URLS 1 to 5.

I also need a pattern than only match URL 6 and 7.

It seems like the negative lookahead will do the trick, except I don't know how to put it together. Can someone help me out?

Something like:

^\/services\/(?:[^\/]+\/?)*$


OR

^/services\/...any Depth here...\/(?!staff)

Answer 1

Regex to match the following:

/services
/services/EarNoseThroat
/services/EarNoseThroat/Audiology
/services/EarNoseThroat/Audiology/CochlearImplant
/services/BehavioralHealth/Clinic  

Regex:

^\/services\/(?!.*\bstaff\b).*$

Click for Demo

Explanation:

• ^ - asserts the start of the string
• \\/services\\/ - matches /services/
• (?!.*\\bstaff\\b) - negative lookahead to make sure that the word staff does not appear anywhere in the string
• .* - matches 0+ occurrences of any character except a newline character
• $ - asserts the end of string

Regex to match the following:

/services/BehavioralHealth/Clinic/staff
/services/BehavioralHealth/Clinic/staff/Jamie-Hudgins

Regex:

^\/services\/(?=.*\bstaff\b).*$

Click for Demo

Explanation:

The only difference is the positive lookahead:

• (?=.*\\bstaff\\b) - positive lookahead to make sure that the word staff appears somewhere in the string before the end of the string