如何使用python分隔连字符分隔的负浮点数？

Question

I have a list containing floating numbers (positive or negative) which are separated by a hyphen. I would like to split them.

For example:

input: -76.833-106.954, -76.833--108.954
output: -76.833,106.954,-76.833,-108.954

I've tried re.split(r"([-+]?\\d*\\.)-" , but it doesn't work. I get an invalid literal statement for int()

Please let me know what code would you recommend me to use. Thank you!

Answer 1

Completing @PyHunterMan's answer:

You want only one hyphen to be optional before the number indicating a negative float:

import re

target = '-76.833-106.954, -76.833--108.954, 83.4, -92, 76.833-106.954, 76.833--108.954'
pattern = r'(-?\d+\.\d+)' # Find all float patterns with an and only one optional hypen at the beggining (others are ignored)
match = re.findall(pattern, target)

numbers = [float(item) for item in match]
print(numbers) 

>>> [-76.833, -106.954, -76.833, -108.954, 83.4, 76.833, -106.954, 76.833, -108.954]

You will notice this does not catch -92 and besides -92 is part the Real numbers set, is not written in float format.

If you want to catch the -92 which is an integer use:

import re

input_ = '-76.833-106.954, -76.833--108.954, 83.4, -92, 76.833-106.954, 76.833--108.954'
pattern = r'(-?\d+(\.\d+)?)'
match = re.findall(pattern, input_)

print(match)

result = [float(item[0]) for item in match]
print(result) 

>>> [-76.833, -106.954, -76.833, -108.954, 83.4, -92.0, 76.833, -106.954, 76.833, -108.954]