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CodeIgniter中的URI路由导致404错误

[英]URI routing in CodeIgniter causes 404 error

Second EDIT - Found the Problem, and answered it as well . 第二次编辑- 找到了问题,并回答了它 First Edit - added my Post_model.php file as well for clearer explanation of my code. 第一次编辑-也添加了我的Post_model.php文件,以便更清晰地解释我的代码。 I am trying to redirect a Blogs slug to a separate page where I can show the entire blogs content. 我正在尝试将Blog条目重定向到一个单独的页面,在其中可以显示整个Blog的内容。

here's an example slug 这是一个例子

http://localhost/aag/posts/test-one 

Here's the Posts controller 这是Posts控制器

<?php   
class Posts extends CI_Controller {
    public function index(){
         // Shows a blog listing

    }

    public function view($slug = NULL){
        $data['post'] = $this->post_model->get_posts($slug);
        if(empty($data['post'])){
            show_404();
        }
        $data['title'] = $data['post']['title'];

        $this->load->view('templates/header');
        $this->load->view('posts/view', $data);
        $this->load->view('templates/footer');

    }
}

The posts/view.php file posts/view.php文件

<h2><?php echo $post['title']; ?></h2>
<small class="post-date">Created on <?php echo $post['created_at']?></small><br>
<div class="post-body">
    <?php echo $post['body']; ?>
</div>

the Post_model.php Post_model.php

class Post_model extends CI_Model
{
    public function __construct()
    {
        $this->load->database();
    }

    public function get_posts($slug = FALSE)
    {
        if ($slug === FALSE) {
            $query = $this->db->get('posts');
            return $query->result_array();
        }
        $query = $this->db->get_where('posts', array('slug' => '$slug'));
        return $query->row_array();
    }
}

routes.php

$route['posts/(:any)'] = 'posts/view/$1';
$route['posts'] = 'posts/index';
$route['(:any)'] = 'pages/view/$1';

Okay, so years of writing mysqli queries made me do this mistake. 好吧,这么多年编写mysqli查询使我犯了这个错误。 In my Post_model.php I am getting the data where (DB column field) slug should match the $slug that gets passed in, but I surrounded the slugs inside single quotes that was causing the error. 在我的Post_model.php我得到的数据(数据库列字段)段slug应该与传入的$slug相匹配,但是我将段$slug包围在引起错误的单引号内。 Here's the working code now. 这是现在的工作代码。

class Post_model extends CI_Model
{
    public function __construct()
    {
        $this->load->database();
    }

    public function get_posts($slug = NULL)
    {
        if ($slug === NULL) {
            $query = $this->db->get('posts');
            return $query->result_array();
        }
        $query = $this->db->get_where('posts', array('slug' => $slug));
        return $query->row_array();
    }
}

TLDR: Don't encapsulate your passed in arguments inside quotes. TLDR:不要将传入的参数封装在引号内。

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