[英]AngularJS ng-repeat over an array with filter
I have a JS array of objects. 我有一个对象的JS数组。
$scope.users = [{
"name": "alice",
"city": "london",
"wards": [{
"id": 1,
"number": 24
},
{
"id": 2,
"number": 25
},
{
"id": 3,
"number": 26
}
]
},
{
"name": "bob",
"city": "london",
"wards": [{
"id": 1,
"number": 24
},
{
"id": 2,
"number": 25
},
{
"id": 4,
"number": 27
}
]
}
]
I have a ng-repeat="user in users | filter: searchUser
我的
ng-repeat="user in users | filter: searchUser
有一个ng-repeat="user in users | filter: searchUser
Here searchUser
can contain name , city and ward number . 这里
searchUser
可以包含姓名 , 城市和病房号 。 Now the search is working fine for name and city but not for the sub array of objects wards to search for ward number . 现在,对于名称和城市 ,搜索工作正常,但对于要搜索病房号的对象病房的子阵列却不能。
Is there an angularJS way with which I could achieve this? 有没有我可以实现的angularJS方法?
No. You need to write your own custom filter. 否。您需要编写自己的自定义过滤器。
Here is a sample jsfiddle, tested with input search 这是一个示例jsfiddle,已通过输入搜索进行了测试
alice, bob, london, 26, 27 爱丽丝,鲍勃,伦敦,26,27
http://jsfiddle.net/1dura7m3/ http://jsfiddle.net/1dura7m3/
If you want exact match, then change -1 to 0 如果要精确匹配,则将-1更改为0
app.filter('myFilter', function(){
return function(users, search){
if(!search) return users;
if(!users || !users.length) return users;
searchInLower = search.toString().toLowerCase();
users = users.filter(function(user){
matches = false;
if(user.name){
usernameInLower = user.name.toString().toLowerCase();
matches = matches || usernameInLower.indexOf(searchInLower) !== -1;
}
if(user.city){
cityInLower = user.city.toString().toLowerCase();
matches = matches || cityInLower.indexOf(searchInLower) !== -1;
}
if(user.wards && user.wards.length && !matches){
for(var i = 0; i < user.wards.length; i++){
ward = user.wards[i];
for(var key in ward){
objectKeyValueInLower = ward[key].toString().toLowerCase();
matches = matches || objectKeyValueInLower.indexOf(searchInLower) !== -1;
}
}
}
return matches
});
return users;
}
})
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