无法将名称和日期与字典分开以将其写入Excel文件

Question

I've created a script in python to parse the business names and their dates from a webpage and write them to an excel file using openpyxl. My intention is to place the names and dates in seperate columns like name1 date1 name2 date2 and so on.

My current attempt can fetch the content in a dictionary and produces the result like below:

{'NATIONAL OPERA STUDIO': '18 Nov 2010', 'NATIONAL THEATRE BALLET SCHOOL': '12 Aug 2005', 'NATIONAL THEATRE DRAMA SCHOOL': '12 Aug 2005', 'NATIONAL THEATRE': '30 Mar 2000'}

How can I place the names and dates in an excel file like following?

column1                 column2       column3                           column4  
NATIONAL OPERA STUDIO   18 Nov 2010   NATIONAL THEATRE BALLET SCHOOL    12 Aug 2005

This is my try so far:

import re
import requests
from bs4 import BeautifulSoup
from openpyxl import load_workbook

wb = load_workbook('container.xlsx')
ws = wb['Sheet1']

url = "https://abr.business.gov.au/ABN/View?id=78007306283"

response = requests.get(url)
soup = BeautifulSoup(response.text,'lxml')
try:
    names_n_dates = {item.find("a").get_text(strip=True):' '.join(item.find("a").find_parent().find_next_sibling().text.split()) for item in soup.find("th",text=re.compile("Business name",re.I)).find_parent().find_next_siblings("tr")}
except AttributeError: names_n_dates = ""

items = {k:v for k,v in names_n_dates.items()}
print(items)

ws.append([items.split()])
wb.save("container.xlsx")

I know I can't apply split function on dictionary but I don't know any alternative option eiter to achieve the same. I used ws.append([]) to include the fields in an excel file and I wish to keep this command as it is because there are other fields to include within it later.

Answer 1

If you want to keep ws.append() as you appear to intend (appending one list as one row), then do this:

import re
import requests
from bs4 import BeautifulSoup
from openpyxl import load_workbook

wb = load_workbook('container.xlsx')
ws = wb['Sheet1']

url = "https://abr.business.gov.au/ABN/View?id=78007306283"

response = requests.get(url)
soup = BeautifulSoup(response.text,'lxml')
try:
    names_n_dates = {item.find("a").get_text(strip=True):' '.join(item.find("a").find_parent().find_next_sibling().text.split()) for item in soup.find("th",text=re.compile("Business name",re.I)).find_parent().find_next_siblings("tr")}
except AttributeError: names_n_dates = ""

row = []

for item in names_n_dates.items():
   for column in item:
       row.append(column)

ws.append(row)

wb.save("container.xlsx")

Answer 2

To solve this you can iterate over the dictionary items that are tuples of (key, value), and then get the key and value of each one of those items like a list. The key is in position 0 of the item and value is in position 1.

import re
import requests
from bs4 import BeautifulSoup
from openpyxl import load_workbook

wb = load_workbook('container.xlsx')
ws = wb['Sheet1']

url = "https://abr.business.gov.au/ABN/View?id=78007306283"

response = requests.get(url)
soup = BeautifulSoup(response.text,'lxml')
try:
    names_n_dates = {item.find("a").get_text(strip=True):' '.join(item.find("a").find_parent().find_next_sibling().text.split()) for item in soup.find("th",text=re.compile("Business name",re.I)).find_parent().find_next_siblings("tr")}
except AttributeError: names_n_dates = ""

row = []

for item in dict.items(): #iterate over all dict items
   row.append(item[0]) #key
   row.append(item[1]) #value

ws.append(row)

wb.save("container.xlsx")