如何对多维数组中的多列数据进行排序？

Question

I am working with a Javascript code where I have an array like below:

Array:

[
    ["2015-08-09", 1.2, 1.20, 2.1],
    ["2015-08-10", 1.2, 1.21, 2.11],
    ["2015-08-11", 1.2, 0.99, 2.20],
    ["2015-10-29", 1.2, 1.12, 2.22],
    ["2015-09-10", 1.21, 1.19, 2.00]
]

My required Result is:

[
    ["2015-08-09", 1.20, 1.20, 2.10],
    ["2015-08-10", 1.20, 1.21, 2.11],
    ["2015-08-11", 1.20, 0.99, 2.20],
    ["2015-10-29", 1.20, 1.12, 2.22],
    ["2015-09-10", 1.21, 1.19, 2.00]
]

As the array is 3 dimensional I want to sort on column 1 and 2 , so first apply ascending on column 1 and then column 2 (Ascending/descending).

Thanks In Advance.

Answer 1

I also face the same issue and found a good solution for sort multiple columns data in Multi-Dimensional array.

Check the below code

 (function() { function deepsort(){ var i, order= arguments, L= order.length, tem; return a.sort(function(a, b){ i= 0; while(i < L){ tem= order[i++]; var res = tem.split("_"); var ao= a[res[0]] || 0, bo= b[res[0]] || 0; if(ao== bo) continue; if(res[1] == "ASC"){ return ao > bo? 1: -1; } if(res[1] == "DESC"){ return ao < bo? 1: -1; } } return 0; }); } var a= [ ["2015-08-09", 1.2, 1.20, 2.1], ["2015-08-10", 1.2, 1.21, 2.11], ["2015-08-11", 1.2, 0.99, 2.20], ["2015-10-29", 1.2, 1.12, 2.22], ["2015-09-10", 1.21, 1.19, 2.00] ]; document.write(deepsort(1+"_ASC",2+"_ASC")); // for better result view check console log console.log(deepsort(1+"_ASC",2+"_ASC")) //console.log(a.deepsort(1)) })(); 

Answer 2

Here you have another approach using a more like mathematical expression on the sort comparison function, and also formats the output as you expected:

 const input = [ ["2015-08-09", 1.2, 1.20, 2.1], ["2015-08-10", 1.2, 1.21, 2.11], ["2015-08-11", 1.2, 0.99, 2.20], ["2015-10-29", 1.2, 1.12, 2.22], ["2015-09-10", 1.21, 1.19, 2.00] ]; // First, we use map() to clone the array so we don't change // the original, and also to format the numbers as you expect. let res = input.map( ([a, b, c, d]) => [a, b.toFixed(2), c.toFixed(2), d.toFixed(2)] ); // Now we sort the new array using a more-like mathematical expression. res.sort((x, y) => { let n = x[1] - y[1], m = x[2] - y[2]; return n + m * (n === 0); }); console.log(res); 

Answer 3

Just chain the wanted order by taking the delta of each column.

 var array = [["2015-08-09", 1.2, 1.2], ["2015-08-10", 1.2, 1.21], ["2015-08-11", 1.2, 0.99], ["2015-10-29", 1.2, 1.12], ["2015-09-10", 1.21, 1.19]]; array.sort((a, b) => a[1] - b[1] || a[2] - b[2]); console.log(array.map(a => a.join(' '))); 

Answer 4

Actually your array is 2-dimensional. You can sort it the same way as 1-dimensional array:

 const data = [ [ "2015-08-09", 1.2, 1.2], [ "2015-08-10", 1.2, 1.21], [ "2015-08-11", 1.2, 0.99], [ "2015-10-29", 1.2, 1.12] , [ "2015-09-10", 1.21, 1.19] ] function sort(a, b) { const col1 = new Date(a[0]) - new Date(b[0]); if (col1 === 0) { return a[1] - b[1]; } return col1; } console.log(data.sort(sort)) 

In above example we sort first by the first field in inner array. If values are equal - then we compare the second field of inner array.