Gulp正在编译每个Js文件

Question

i have a problem with my gulp.
Its works fine and its really fast but Gulp is compiling all js files in my project...

my gulp-watch:

gulp.task('watch', function () {
    gulp.watch(sassFilesWatch, ['styles']);
    gulp.watch(jsFilesWatch, ['uglify'])
});

My array:

var jsFilesWatch = [
    'clients/*/template/lib/jscripts/*.js',
    'clients/*/template/modules/**/*.js',
    'system/lib/jscripts/*.js',
    'system/mod/**/*.js',
    'clients/core/modules/**/*.js',
    '!/**/*.min.js'
];

Thats my function:

gulp.task('uglify', function(){
    pump([
        gulp.src(jsFilesWatch, {
            base: './'
        }),
        debug({
            title: 'Compiled',
            showFiles: false,
        }),
        uglify(),
        rename({ suffix: '.min' }),
        gulp.dest('./')
    ]);
});

And thats the output:
Output

Just my saved file should be compiled how can i do that?

thanks alot

Answer 1

It seems all your files with .js extensions are being debugged, uglified and minified. Which saved file are you trying to compile?

**/*.js uses the gulp command to watch all files with the .js extension in all folders.

You could use .pipe()

var uglify = require('gulp-uglify'),
concat = require('gulp-concat');

gulp.task('js', function() {
gulp.src('scripts/*.js')
.pipe(uglify())
.pipe(concat('script.js'))
.pipe(gulp.dest('assets'))
});

Answer 2

Have a look into this Plugin, That will solve your problem

https://www.npmjs.com/package/gulp-changed

Try Changing your task to,

gulp.task('uglify', function(){
    pump([
        gulp.src(jsFilesWatch, {
            base: './'
        }),
        changed('dist'),
        ngAnnotate(),
        debug({
            title: 'Compiled',
            showFiles: false,
        }),
        uglify(),
        rename({ suffix: '.min' }),
        gulp.dest('./')
    ]);
});

Note: this might run all your .js files at first time after you run your task, but it will identify the changed file on subsequent runs