如何使用无服务器框架将环境变量传递给AWS Lambda函数？

Question

I am using the aws-node template. I want to do something like this:

sls deploy URL='https://postman-echo.com/post'

Where URL is the environment variable. I am trying to pass this env variable to my serverless.yml

provider:
  name: aws
  runtime: nodejs8.10
  stage: dev
  region: us-west-2
  environment:
    URL: ${env:URL}

Then access it in my handler.js

const axios = require('axios');

module.exports.hello = async (event, context) => {

  console.log("Lambda invoked\n")

  await axios.post(
    process.env.URL // Accessing the environment variable.
  ).then(function (response) {
      console.log(`Status: ${response.status}`)
    })
    .catch(function (error) {
      console.log(`Error`)
      console.error(error);
    });


  return {
    statusCode: 200,
    body: JSON.stringify({
      message: 'Function executed successfully!',
      input: event
    }),
  };

};

I susspect that the issue is in how I am passing the environment variable to the program but my research has been to no avail.

Answer 1

Don't pass the variable along with the deploy command. Instead set it from the terminal first:

In your terminal, run:

URL='https://postman-echo.com/post'

and then run

sls deploy

Alternatively, you can use a plugin:

Here's a plguin to that: https://github.com/colynb/serverless-dotenv-plugin

npm i -D serverless-dotenv-plugin

then add the plugin to your config file:

service: myService
plugins:
  - serverless-dotenv-plugin
...

create your usual dotenv file .env and then access as usual:

...
provider:
  name: aws
  runtime: nodejs6.10
  stage: ${env:STAGE}
  region: ${env:AWS_REGION}
...

And if you really need to run it from the console with different urls flags, (though I'd recommend using just one .env file without the command flags) do this:

Put your different urls in: .env.url1 .env.url2 .env.url3

and then:

sls deploy --env url1

Answer 2

The code that you posted works. You just have to pass URL as an environment variable and NOT as an argument.

This should work (passing URL as an environment variable):

$ URL='https://postman-echo.com/post' sls deploy

This won't work (you're passing URL as an argument to sls deploy ):

$ sls deploy URL='https://postman-echo.com/post'