如何使用递归打印1到5和5到1？
[英]how to print 1 to 5 and 5 to 1 using recursion…?
问题描述
I wanted to print numbers 5-0 then 0-5 in the order with shortest Lines of code. 
我想按最短代码行的顺序打印数字5-0然后是0-5。 Here's what I implemented. 这是我实现的。 However, looking for any other logic with less number of lines of code. 但是，寻找其他更少代码行的逻辑。 Looking forward for your replies please. 请期待您的答复。 Thanks, 谢谢，
<html>
<body>
<script>
var n;
function count(n){
console.log(n);
if(n>=1){
return count(n-1);
}
else{
n=1;
count2(n);
}
}
function count2(n){
console.log(n);
if(n<5){
count2(n+1);
}
}
count(5);
</script>
</body>
</html>
6 个解决方案
解决方案1
3 2019-01-27 15:49:39
Your recursive attempt could be written like this: 您的递归尝试可以这样写：
function count(n, limit=-n){ console.log(Math.abs(n)); if (n>limit) count(n-1, limit); } count(5);
In a non-recursive version it would be: 在非递归版本中，它将是：
function count(n) { for (let i = -n; i <= n; i++) console.log(Math.abs(i)); } count(5);
解决方案2
2 2019-01-27 15:42:03
you have no need to use recursion for this. 您无需为此使用递归。 Simply use for loops 只需使用循环
let number = 5
//from 1 to your desired number
for(let i = 1;i<=number;i++){
console.log(i);
}
//from your desired number to 1
for(let i = number;i>0;i--){
console.log(i);
}
解决方案3
2 2019-01-27 15:56:01
Changing the step: 更改步骤：
function ctn(num) {
let i = -1, n = num++;
do {
console.log(n);
n || (i = 1);
} while ( (n += i) < num);
}
解决方案4
1 2019-01-27 15:47:51
You can use iteration. 您可以使用迭代。 smallest i can think of 我能想到的最小的
console.log('forward'); [...'12345'].forEach(e=>console.log(e)); console.log('reverse'); [...'54321'].forEach(e=>console.log(e));
解决方案5
0 2019-01-27 15:53:07
It can take any no., any increment (inc) 可以取任何编号，可以任意增加（增量）
const print = (i=5, flow=1, inc=-1) => { console.log(i); if(i===0 && flow===1){ print(i+1,flow+1, 1); return; } if(i===5 && flow===2){ return; } print(i+inc, flow, inc); } print();
解决方案6
0 2019-01-29 23:09:28
Here is a version using generators just for the sake of it! 这是仅出于此目的而使用生成器的版本！
It creates an array from the output and does the console.log all in one go. 它从输出创建一个数组，然后一次完成console.log。
function* count(n, max = n) { yield n > 0 ? n : -n; if (n > -max) yield* count(n-1, max); } console.log(Array.from(count(5)))
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