从文本文件中读取名称列表到2D数组中

Question

I'm trying to read a column of names from a text file into a two dimensional array, the names vary in length but are at max 8 letters long, and there are 10 of them. Here are my two for loops to read the names and then to print them.

for (int i = 0; i != 10; i++) {
    for (int j = 0; j != 8; j++) {
        infile >> textfileinfo[i][j];
    }
}

and then to print the names out I have this loop.

for (int i = 0; i != 10; i++) {
    for (int j = 0; j != 8; j++) {
        cout << textfileinfo[i][j];
    }
    cout << " " << endl;
}

Here is the list of names:

Victor
Eve
Juliet
Hector
Danielle
Romeo
Oscar
June
Ares
Dannae

What ends up happening is it will read the names out with 8 characters regardless, taking the extra characters from the next name, so Victor turns into VictorEv , then eJulietH and so on. How do I get it to start on the next row once the end of Victor is reached, and then move on to Eve etc. I am not allowed to use pointers either. Any help is appreciated! Thanks.

Answer 1

Seems the obvious thing is to use getline . getline is designed to read a single line of text.

for (int i = 0; i != 10; i++) {
     infile.getline(textfileinfo[i], 9);
}

Note that the second argument to getline is 9 because you need an extra character to store the nul terminator that ends every C style string. This also mean that your 2D array need to be declared with at least 9 characters in each row. Slightly safer code would be to make this explicit

infile.getline(textfileinfo[i], sizeof textfileinfo[i]);

If for some reason you aren't allowed to use getline then you going to have to modify your inner loop to detect and deal with the '\\n' character that terminates every line.