使用正则表达式在 Java 中拆分字符串

Question

I am getting an input from the user as a String, input example are like this:

Hospital name 123-4567   (Hospital name = name, 123-4567=ZIP CODE)
Hospital 123-4567        (Hospital = name, 123-4567=ZIP CODE)
Hospital 33name 123-4567 (Hospital 33name = name, 123-4567=ZIP CODE)
123-4567                 (123-4567=ZIP CODE)
1234567                  (1234567=ZIP CODE)

Now I found a regex to recognize the ZIP CODE: [0-9]{3}[-,ー]?[0-9]{4} (first are 3 number, then 4 number after -,ー) But I want to split the string in 2 parts: name and zip code. If I split with this regex the string: HOSPITAL NAME 123-4567

I get a variable with only: HOSPITAL NAME, and the ZIP CODE isn't "divided" in another variable / list.

I have to separate the 2 parts in 2 different variable / list / array, everything is fine.

Than is not all, in the user inputbox, every character inputted is processed, so I have to recognize the string on every input.

If the user start to input: HOSPITAL NAME 3 (I can guess that this 3 is the start of the ZIP CODE or still the name of the hospital, but if the input continue with: HOSPITAL NAME 345-, I'm sure that 345- is the ZIP CODE)

Anyone know how to DIVIDE this sting in 2 parts?

Answer 1

Assuming that inputLine is a single line to parse (eg Hospital name 123-4567 )

Pattern pattern = Pattern.compile("(?:(.*)\\s+)?(\\d{3}[-ー]?\\d{4})"):
Matcher matcher = pattern.matcher(inputLine);
matcher.matches();
//use matcher.group(1) for the hospital name (e.g. "Hospital name")
//use matcher.group(2) for the zip code (e.g. "123-4567")

This regex will work for your purposes.