[英]fscanf not saving line - C
I'm trying to scan a line from a open file pointer, the one passed to the function is stdin. 我正在尝试从打开的文件指针扫描一行,传递给该函数的是stdin。 When I print out the value of input I get (null).
当我打印出输入值时,我得到(空)。 Any ideas why fscanf is not saving the value?
任何想法为什么fscanf不能保存价值? This is the code — also shown below:
这是代码 -也如下所示:
char *ReadLineFile(FILE *infile){
char *input;
char buf[MAX];
//check if file pointer is at end of file
if(feof(infile))
return NULL;
//scan from file
fscanf(infile,"%s",input);
printf("%s",input);
input = (char *)malloc(strlen(input)+1);
//handle memory allocation errors
if (input == NULL){
printf("Error allocating memory\n");
return "error";
}
fclose(infile);
return input;
}
You must allocate memory for input
before using fscanf(infile,"%s",input);
使用
fscanf(infile,"%s",input);
之前,必须为input
分配内存fscanf(infile,"%s",input);
. 。
fscanf(infile,"%s",input);
asks fscanf
to read a string and write it to input
. 要求
fscanf
读取一个字符串并将其写入input
。 Since input
has not been assigned a value, let alone a value that points to memory allocated for this, the behavior is not defined. 由于尚未为
input
分配值,更不用说指向为此分配的内存的值了,因此未定义行为。
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