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如何从表中获取数据,该数据在cakePHP的联接表中不可用

[英]how to get data from a table which data is not available in joined table in cakePHP

I am using cakePhp 3.6, I have two table. 我正在使用cakePhp 3.6,我有两个表。 Both are joined. 两者都加入了。 In one table I have some token table name is codes and on another table I have stored some code for some venue. 在一个表中,我有一些token表名称是codes ,在另一个表中,我存储了一些场所的code Table name is venues_codes . 表格名称是venues_codes
Like I have 10 code in codes table. 就像我在codes表中有10个code And in venues_codes table 5 code is stored for some vanue. 而在venues_codes表5 code存储一些vanue。 This is the structure for venues_codes table. 这是venues_codes表的结构。 id venue_id code_id . id venue_id code_id Here venue_id is coming from another table. 在这里, venue_id来自另一个表。 It is not my concern now. 现在不用担心了。 I just want to get the rest five code from codes table that is not available in venues_codes table. 我只想从venues_codes codes表中不可用的codes表中获取其余五个code

This is how I have tried, but it is only fetching token that is available in both table. 这是我尝试过的方法,但是只能获取两个表中都可用的token

$this->loadModel('VenueCodes');
$this->loadModel('Codes');
$query = $this->VenueCodes->find()
->contain(['Codes'])
->select(['id','code_id']);`

I am working with CakePHP. 我正在使用CakePHP。 But if anyone can help me with the normal sql logic, that also will be helpful for me. 但是,如果有人可以用常规的sql逻辑帮助我,那也将对我有所帮助。

这应该为您提供所有未连接到场所的代码:

$codes = $this->Codes->find()->notMatching('Venues');

纯mysql查询如下所示:

 SELECT code FROM codes WHERE code NOT IN (SELECT code_id FROM venues_codes);

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