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定义整数列表的函数,使它们的和为n

[英]Define function of list of integers such that their sum is n

I am trying to solve the following problem with Haskell: 我正在尝试使用Haskell解决以下问题:

Problem 问题

Define the function sumToLists :: Int -> [[Int]] that, given a natural number n , it returns all the lists of positive numbers such that their sum is n . 定义函数sumToLists :: Int -> [[Int]] ,给定自然数n ,该n返回所有正数列表,使它们的和为n

I am pretty lost at this problem, maybe using recursion could yield up a solution but I have no clue how to attack this. 我对这个问题很困惑,也许使用递归可以得出一个解决方案,但是我不知道如何解决这个问题。 Any suggestions would be greatly appreciated 任何建议将不胜感激

sumToLists 0 = [[]]
sumToLists n = [ i: xs | i <- [1..n], xs <- sumToLists (n - i) ] 

you need special case for 0 because default will return [] not [[]] . 您需要将0用作特殊情况,因为默认值将返回[]而不是[[]]

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