使用多条件 SQL 的左连接

Question

I am trying to make an application that will display every other user that is not the logged in user or that the logged in user does not not follow (like an explore page), but I'm having trouble writing the SQL query.

My tables are set up as:

following(username1, username2)

(meaning username1 follows username2)

and

users(username, fullname, ...)

Right now I am trying to do something like:

SELECT * FROM
users u 
LEFT JOIN following f ON (
  u.username != 'loggedInUser'
  AND f.username1 = 'loggedInUser'
  AND f.username2 = u.username
)

I replace loggedInUser in a Python script.

Unfortunately, this query is currently returning all of my users, and it should not be. I'm having a lot of issues working though this logic for some reason, does anyone have some insight?

Answer 1

This will display every other users that are not the logged in user and (not or) that the logged in user does not not follow (them):

SELECT * 
FROM users u 
WHERE u.username <> 'loggedInUser'
    AND NOT EXISTS (
            SELECT 1
            FROM following f
            WHERE f.username1 = 'loggedInUser'
                AND f.username2 = u.username
        );

Your query could change to an INNER JOIN to get expected result but it may be more complicated with worse performance:

SELECT DISTINCT u.* 
FROM users u 
INNER JOIN following f 
ON f.username1 <> 'loggedInUser'
    OR f.username2 <> u.username
WHERE u.username <> 'loggedInUser';

Answer 2

If you need to get all the users not followed by the logged in user, just try the below script.

SELECT * FROM
users u 
where u.username in(select username2 from following where username1!= 'loggedInUser')
and u.username!='loggedInUser'

Answer 3

SELECT * FROM
users u 
LEFT JOIN following f ON u.[insert_primary_key_here]=f.[insert_foreign_key_here] 
WHERE u.username != 'loggedInUser'
AND f.username1 = 'loggedInUser'
AND f.username2 = u.username

Answer 4

Why don't you simply create a new column in users of bit type that will be updated when any user is being logged in . Then you just have to write a simply query that would be

Select * from users where loggedIn=1

that will return you all the users data with logged in status