根据包含来自另一个数组的所有值的数组属性过滤对象数组

Question

I have an array of objects:

const breeds=[{name: 'Golden', temperament: ['friendly', 'kind', 'smart']},{name: 'Husky', temperament: ['alert', 'loyal', 'gentle']},{name: 'Yorkshire Terrier', temperament: ['bold', 'independent', 'kind']}]

I would like to sort them by selected "temperament." Let's say a user has selected both "kind" & "friendly", it should only return "Golden".

I'm using javascript and underscore and this is what I have tried so far:

 //selected is an array of selected temperaments
 //breeds is the array of objects
function filterTemperaments(selected, breeds) {
  return _.filter(breeds, function (breed) {
    if (!breed.temperament) breed.temperament = "";
    const breedList = breed.temperament;
    return breedList.includes(...selected);
  }, selected);
}

This seems to only be returning breeds that match the first temperament in the selected array. For example if selected is ['kind', 'loyal'] and the breed is {name:'Golden', temperament: ['kind', 'smelly']} , Golden will still come back as true, despite not matching the "Loyal" temperament

Any thoughts for a better solution here? Thanks in advance!!

Answer 1

You can use filter to return only those breeds which have every temperament selected

 const breeds=[{name: 'Golden', temperament: ['friendly', 'kind', 'smart']},{name: 'Husky', temperament: ['alert', 'loyal', 'gentle']},{name: 'Yorkshire Terrier', temperament: ['bold', 'independent', 'kind']}], selected = ['kind', 'friendly'] const filtered = breeds.filter(b => selected.every(s => b.temperament.includes(s))) console.log(filtered) 

Answer 2

it is easy to use using filter and every in order to know if you got any matches and return the matched values.

 const breeds = [{ name: 'Golden', temperament: ['friendly', 'kind', 'smart'] }, { name: 'Husky', temperament: ['alert', 'loyal', 'gentle'] }, { name: 'Yorkshire Terrier', temperament: ['bold', 'independent', 'kind'] }] //selected is an array of selected temperaments //breeds is the array of objects function filterTemperaments(selected, breeds) { return breeds.filter(({ temperament }) => { //here I'm desctructuring the object only to get the temperaments. return selected.every(selection => temperament.indexOf(selection) !== -1) }) } const result = filterTemperaments(['kind', 'friendly'], breeds); console.log(result)