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在复杂地图中对列表进行排序

[英]Sorting a List inside a complex map

I need help, i could not find a way to resolve this task.. 我需要帮助,我找不到解决此任务的方法。

I created this map from an ArrayList in following way: 我通过以下方式从ArrayList创建了此映射:

Map<RamiBean, Map<String, Map<String, List<AllertaBean>>>> complexMap = allerte.stream()
    .distinct()
    .collect(Collectors.groupingBy(
             ab -> ab.getRamoBean(), 
             Collectors.groupingBy(ab -> ab.getPuntoBean().getNomePunto(), 
             Collectors.groupingBy(AllertaBean::getDescAllerta))));

My problem is that i need to group the second level for ab.getPuntoBean().getNomePunto() but i I would like to have this group ordered by another field/method: ab.getPuntoBean().getKm() 我的问题是我需要将第二层的ab.getPuntoBean().getNomePunto()但是我想按另一个字段/方法对这个组进行排序: ab.getPuntoBean().getKm()

try this 尝试这个

Map<RamiBean, Map<String, Map<String, List<AllertaBean>>>> complexMap = allerte.stream()
    .distinct()
    .collect(Collectors.groupingBy(
         ab -> ab.getRamoBean(), 
         Collectors.groupingBy(ab -> ab.getPuntoBean().getNomePunto(), 
         Collectors.toMap(
                 AllertaBean::getDescAllerta,
                 ab -> new ArrayList(Arrays.asList(ab)),
                 (abList1, abList2) -> {
                       abList1.addAll(abList2);
                       abList1.sort(Comparator.comparing(ab -> ab.getPuntoBean().getKm()))
                       return abList1;
                  }
         )
         )
    ));

or this one 或这个

Map<RamiBean, Map<String, Map<String, List<AllertaBean>>>> complexMap = allerte.stream()
    .distinct()
    .collect(Collectors.groupingBy(
         ab -> ab.getRamoBean(), 
         Collectors.groupingBy(ab -> ab.getPuntoBean().getNomePunto(), 
         Collectors.groupingBy(AllertaBean::getDescAllerta,
              Collectors. collectingAndThen(Collectors.toList(),
                   abList -> abList.sort(Comparator.comparing(ab -> ab.getPuntoBean().getKm()))
  ))));

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