[英]how to get fields and values from a specific key of json file in python
I am trying to return the fields and values of a specific key but getting error Here is the sample json format: 我正在尝试返回特定键的字段和值,但出现错误,这是示例json格式:
"results": [
{
"time": "00:00",
"app_name": "dcg",
"avg": "7717"
},
{
"time": "00:00",
"app_name": "pds",
"avg": "75.40223463687151"
},
{
"time": "00:00",
"app_name": "rdts",
"avg": "1481.5555555555557"
},
{
"time": "00:00",
"app_name": "slbl",
"avg": "786"
},
{
"time": "01:00",
"app_name": "pds",
"avg": "36.4765625"
}
here is my code 这是我的代码
import json
json_data=open("some.json")
jdata = json.load(json_data)
for k, v in jdata.results.items():
for k1, v1 in v.items():
print(k1)
print(v1)
Please note results is key and time field having multiple entries with same value. 请注意,结果是键和时间字段,其中包含多个具有相同值的条目。
Apart from fixing the broken indent, you can try the following. 除了修复损坏的缩进,您还可以尝试以下方法。
results
is a key of your dictionary whose value can be accessed as jdata["results"]
. results
是字典的键,其值可以作为jdata["results"]
进行访问。
for v in jdata["results"]:
for k1, v1 in v.items():
print(k1)
print(v1)
EDIT : To store them in a list, you can do 编辑 :要将它们存储在列表中,您可以执行
result = []
for v in jdata["results"]:
for k1, v1 in v.items():
result.append({"k1":v1})
[{'k1': '00:00'},
{'k1': 'dcg'},
{'k1': '7717'},
{'k1': '00:00'},
{'k1': 'pds'},
{'k1': '75.40223463687151'},
{'k1': '00:00'},
{'k1': 'rdts'},
{'k1': '1481.5555555555557'},
{'k1': '00:00'},
{'k1': 'slbl'},
{'k1': '786'},
{'k1': '01:00'},
{'k1': 'pds'},
{'k1': '36.4765625'}]
I had to put your JSON in a containing set of brackets {} otherwise the JSON processor can't parse it.... 我必须将您的JSON放在一组包含括号的{}中,否则JSON处理器无法解析它。
ie.. 即..
{ 'result' : [...] }
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