Py2app找不到工作目录

Question

I keep get this error when i run my py2app. It works when i do python app.py and when it runs as a terminal, however it doesnt work when its built to work as an py2app

It's a scrapy project.

app.py

import os
from subprocess import call


def main():
    cw = os.getcwd()
    path = '/scrape'
    cwd = cw + os.path.join(path)
    ourPath = ['scrapy','crawl', 'yellow']
    name = "yellow"
    call(["scrapy", "crawl", "{0}".format(name)], cwd=cwd)

if __name__ == "__main__" :
    main()

Answer 1

The scrape package isn't included in /Contents/Resources folder. Since app.py doesn't include any names from the scrape package, the module graph that is constructed when building the application bundle doesn't consist it.

Build procedure can be updated to include the scrape package using the --package option passed to py2app . ^[1]
However when --package option is provided, scrapy package will be copied in Contents/Resources/lib/python2.X/ . ^[2]
This means that you'll have to resolve the directory of the subprocess command for run in to this new path.

A better way to go about this is to run the scraper directly via the Crawler API and not as a subprocess command where that is feasible. ^[3] With the approach, py2app builds the module graph to include necessary code from scrape package.