我想不出让我的代码循环的方法

Question

I am complete starter and i cant figure out how to use the while function in a very simple calucator code.

ive already tried putting the while function in the code in different ways but nothing of it seems to work it just stop without even giving me the final result of the first "problem"

#include "pch.h"
#include <iostream>
using namespace std;

int main()
{

    int number1;
    int number2;
    char op;
    int result;

    cout << "Give first number: ";
    cin >> number1;

    cout << "Give second number: ";
    cin >> number2;

    cout << "Chose operator(+ - / * ): ";
    cin >> op;

    if (op == '+')
    {
        result = number1 + number2;
    }
    else if (op == '-')
    {
        result = number1 - number2;
    }
    else if (op == '*')
    {
        result = number1 * number2;
    }
    else if (op == '/')
    {
        result = number1 / number2;
    }

cout << "The result is: " << result << endl;

system("pause");
return 0;
}

everything its working fine this way i just want it to loop after the first problem and ask again for another one...

Answer 1

I am complete starter and i cant figure out how to use the while function in a very simple calucator code.

Its time for you to get your hands on a good C++ book ...

Syntax of while loop: while (some_condition) { /* Body... */ }

Rectified code of above problem:

#include <iostream>

int main()
{
    int number1, number2, result;
    char op;
    bool is_loop = true;

    while (is_loop) {
        std::cout << "Give first number: ";
        std::cin >> number1;

        std::cout << "Give second number: ";
        std::cin >> number2;

        std::cout << "Chose operator(+ - / * ): ";
        std::cin >> op;

        switch (op)
        {
        case '+':
            result = number1 + number2;
            break;
        case '-':
            result = number1 - number2;
            break;
        case '*':
            result = number1 * number2;
            break;
        case '/':
            result = number1 / number2;
            break;
        default:
            is_loop = false;
        }
        std::cout << "The result is: " << result << std::endl;
        std::cin.get();
    }
    return 0;
}

Answer 2

you may try something like this.. this might be the simplest way of doing this..

do{
//your calculator code
char ch;
cout<<"Do you want to continue"<<endl;
cin>>ch;
while(ch=='Y'||ch=='y');