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Express-获取router.get返回json数据属性

[英]Express - get router.get to return json data attribute

I am new to javascript and would like to retrieve the json response from my express route get request. 我是javascript新手,想从我的快速路线get请求中检索json响应。 I can return the whole json but when i try to return a specific element i recieve an error (eg res.body.data). 我可以返回整个json,但是当我尝试返回特定元素时,会收到错误消息(例如res.body.data)。 Here is my route file 这是我的路线文件

route.js route.js

var express = require('express');
var router = express.Router();
var request = require('request');
router.get('/', function(req, res, next) {
  request({
    uri: 'https://www.reddit.com/r/meme/new/.json'
  }).pipe(res);
});
module.exports = router;

app.js app.js

var createError = require('http-errors');
var express = require('express');
var path = require('path');
var cookieParser = require('cookie-parser');
var logger = require('morgan');
var cors = require("cors");
var indexRouter = require('./routes/index');
var usersRouter = require('./routes/users');
var testAPIRouter = require('./routes/testAPI');
var route = require('./routes/route');

var app = express();
// view engine setup
app.set('views', path.join(__dirname, 'views'));
app.set('view engine', 'jade');
app.use(cors());
app.use(logger('dev'));
app.use(express.json());

app.use(cookieParser());
app.use(express.static(path.join(__dirname, 'public')));

app.use('/', indexRouter);
app.use('/users', usersRouter);
app.use('/testAPI', testAPIRouter);
app.use('/route', route);
// catch 404 and forward to error handler
app.use(function(req, res, next) {
  next(createError(404));
});

// error handler
app.use(function(err, req, res, next) {
  // set locals, only providing error in development
  res.locals.message = err.message;
  res.locals.error = req.app.get('env') === 'development' ? err : {};

  // render the error page
  res.status(err.status || 500);
  res.render('error');
});
module.exports = app;

You need to use body parser: 您需要使用正文解析器:

const app = express();
const bodyParser = require('body-parser'); 
app.use(bodyParser.urlencoded({ extended: false }));

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