[英]Can't reach by link Spring
I am new with Spring framework and right now I'm trying to learn few things but facing a problem. 我是Spring框架的新手,现在我想学习一些东西,但面临一个问题。 (Learning from this tutorial https://spring.io/guides/gs/rest-service/ ).
(从本教程https://spring.io/guides/gs/rest-service/中学习)。 So by default, I can launch my program via
localhost../greeting
, but what if I want to change the name not like in the website with /greeting?name=xx
, but for example /greeting/Tom..
( /greeting/{name}
) 因此,默认情况下,我可以通过
localhost../greeting
启动程序,但是如果我不想使用/greeting?name=xx
来更改网站名称而不是网站中的/greeting?name=xx
,例如/greeting/Tom..
( /greeting/{name}
)
The thing you need here is called PathVariable. 您在这里需要的东西称为PathVariable。 This article is very useful to understand all the difference between types of requesting
本文对于理解请求类型之间的所有差异非常有用
https://www.quora.com/What-is-the-difference-between-QueryParam-and-pathParam-in-Webservices https://www.quora.com/What-is-the-difference-between-QueryParam-and-pathParam-in-Webservices
In GreetingController: 在GreetingController中:
Instead of this: 代替这个:
@RequestMapping("/greeting")
public Greeting greeting(@RequestParam(value="name", defaultValue="World") String name)
Implement this: 实施此:
@RequestMapping("/greeting/{name}")
public Greeting greeting(@PathVariable("name") String name)
for optional path variable: 对于可选的路径变量:
@PathVariable Optional<String > name
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