比较hive表时如何计算记录的百分比？

Question

Two Hive tables called table1 and table2 are there. I got the count of both of these tables. I created a third table called abc with the non matching records from table1 and table2. How can I get the percentage of number of records in table abc compare to the entire count of table1 and table2?

1. select count(*) from table1 A

2. select count(*) from table2 B
3. create table dbo.abc as 
   select A.column1, A.columnb from table A
   inner join table B
   where A.column3 <> B.column3

4. how to get the percentage of records in table abc? 
    for example:   count(*) from abc 
                   -------------------- *100
                   count(*) from A + B

Expected output is:

Example: 
  number_of_non_matching_records = 20%

Answer 1

Are you trying to do this in one statement?

select count(*) as combos_in_ab,
       sum(case when a.column3 <> b.column3 then 1 else 0 end) as combos_in_3,
       avg(case when a.column3 <> b.column3 then 1.0 else 0 end) as percent_in_3
from a cross join
     b;