[英]Split a string delimited by a list of substrings
I have data like: 我有类似的数据:
str = "CODEA text for first item CODEB text for next item CODEB2 some"\
"more text CODEC yet more text"
and a list: 和清单:
arr = ["CODEA", "CODEB", "CODEB2", "CODEC", ... ]
I want to divide this string into a hash. 我想将此字符串分成一个哈希。 The keys of the hash will be
CODEA
, CODEB
, etc. The values of the hash will be the text that follows, until the next CODE. 哈希的密钥将
CODEA
, CODEB
等哈希值将是下面的文字,直到下一个代码。 The output should look like this: 输出应如下所示:
"CODEA" => "text for first item",
"CODEB" => "text for next item",
"CODEB2" => "some more text",
"CODEC" => "yet more text"
We are given a sting and an array. 我们得到了一个字符串和一个数组。
str = "CODEA text for first item CODEB text for next item " +
"CODEB2 some more text CODEC yet more text"
arr= %w|CODEC CODEB2 CODEA CODEB|
#=> ["CODEC", "CODEB2", "CODEA", "CODEB"]
This is one way to obtain the desired hash. 这是获得所需哈希的一种方法。
str.split.
slice_before { |word| arr.include?(word) }.
map { |word, *rest| [word, rest.join(' ')] }.
to_h
#=> {"CODEA" =>"text for first item",
# "CODEB" =>"text for next item",
# "CODEB2"=>"some more text",
# "CODEC" =>"yet more text"}
See Enumerable#slice_before . 参见Enumerable#slice_before 。
The steps are as follows. 步骤如下。
a = str.split
#=> ["CODEA", "text", "for", "first", "item", "CODEB",
# "text", "for", "next", "item", "CODEB2", "some",
# "more", "text", "CODEC", "yet", "more", "text"]
b = a.slice_before { |word| arr.include?(word) }
#=> #<Enumerator:
# #<Enumerator::Generator:0x00005cbdec2b5eb0>:each>
We can see the (4) elements (arrays) that will be generated by this enumerator and passed to each_with_object
by converting it to an array. 我们可以看到该枚举器将生成的(4)个元素(数组),并将其转换为数组传递给
each_with_object
。
b.to_a
#=> [["CODEA", "text", "for", "first", "item"],
# ["CODEB", "text", "for", "next", "item"],
# ["CODEB2", "some", "more", "text"],
# ["CODEC", "yet", "more", "text"]]
Continuing, 继续,
c = b.map { |word, *rest| [word, rest.join(' ')] }
#=> [["CODEA", ["text for first item"]],
# ["CODEB", ["text for next item"]],
# ["CODEB2", ["some more text"]],
# ["CODEC", ["yet more text"]]]
c.to_h
#=> {"CODEA"=>"text for first item",
# "CODEB"=>"text for next item",
# "CODEB2"=>"some more text",
# "CODEC"=>"yet more text"}
The following is perhaps a better way of doing this. 以下也许是一种更好的方法。
str.split.
slice_before { |word| arr.include?(word) }.
each_with_object({}) { |(word, *rest),h|
h[word] = rest.join(' ') }
When I was a kid this might be done as follows. 当我还是个孩子时,可以按照以下步骤进行操作。
last_word = ''
str.split.each_with_object({}) do |word,h|
if arr.include?(word)
h[word]=''
last_word = word
else
h[last_word] << ' ' unless h[last_word].empty?
h[last_word] << word
end
end
last_word
must be set to anything outside the block. 必须将
last_word
设置为块外的任何内容。
Code: 码:
str = 'CODEA text for first item CODEB text for next item ' +
'CODEB2 some more text CODEC yet more text'
puts Hash[str.scan(/(CODE\S*) (.*?(?= CODE|$))/)]
Result: 结果:
{"CODEA"=>"text for first item", "CODEB"=>"text for next item", "CODEB2"=>"some more text", "CODEC"=>"yet more text"}
Another option. 另外一个选项。
string.split.reverse
.slice_when { |word| word.start_with? 'CODE' }
.map{ |(*v, k)| [k, v.reverse.join(' ')] }.to_h
Enumerator#slice_when
, in this case returns this array: Enumerator#slice_when
,在这种情况下,返回以下数组:
[["text", "more", "yet", "CODEC"], ["text", "more", "some", "CODEB2"], ["item", "next", "for", "text", "CODEB"], ["item", "first", "for", "text", "CODEA"]]
Then the array is mapped to build the required hash to get the result (I did not reversed the Hash): 然后,将数组映射为构建所需的哈希以获取结果(我没有反转Hash):
#=> {"CODEC"=>"yet more text", "CODEB2"=>"some more text", "CODEB"=>"text for next item", "CODEA"=>"text for first item"}
Adding parentheses to the pattern in String#split
lets you get both the separators and the fields. 在
String#split
的模式中添加括号可让您同时获取分隔符和字段。
str.split(/(#{Regexp.union(*arr)})/).drop(1).each_slice(2).to_h
# =>
# {
# "CODEA"=>" text for first item ",
# "CODEB"=>"2 somemore text ",
# "CODEC"=>" yet more text"
# }
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