如何用Python打开文件名中的空格？

Question

I have files that cannot be renamed without white spaces (work files). The file name is Evo PROG6001 FSJD0250240 E.PART stored in a variable file . If I run os.system('start ' "'" + file + "'") it only recognizes the word Evo and returns Windows cannot find "Evo". Make sure you types the name correctly, and then try again Windows cannot find "Evo". Make sure you types the name correctly, and then try again . The same thing occurs with os.system('start ' + file) .

Is there a way to do this?

Answer 1

I needed to use os.startfile() and also point it to the root directory, which I had stored previously.

os.startfile(new_folder + '\\\\' + file) works