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Android - 检查表中是否存在行并更新它

[英]Android - Check if row exists in table and update it

Unfortunately all the solutions I could find, would not help me with my problem.不幸的是,我能找到的所有解决方案都无法帮助我解决问题。

With a button click I want to add some value to my database table, but first it should check if the row already exists in my table, if so it just should update the row.通过单击按钮,我想向我的数据库表添加一些值,但首先它应该检查该行是否已经存在于我的表中,如果存在,它应该更新该行。

Here are my Codes:这是我的代码:

MAIN ACTIVITY: (Just the Button Click)主要活动:(只需单击按钮)

ingredient= new Ingredient();

btnAdd.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        for(int i = 0; i < dataSource.size();i++){
            tvname = (TextView) shoppingList.getChildAt(i).findViewById(R.id.tvName);
            tvamount = (TextView) shoppingList.getChildAt(i).findViewById(R.id.tvAmount);

            String nameTV = tvname.getText().toString();
            String amountTV = tvamount.getText().toString();

            ingredient.setName(nameTV);
            ingredient.setAmount(amountTV);
            ingredient.setId(i);

            TableIngredient.getInstance(IngredientShopping.this).checkRow(ingredient);
            }

DATABASE TABLE:数据库表:

public class TableIncredient extends SQLiteOpenHelper {
    public static TableIngredient INSTANCE = null;

    public static final String DB_NAME = "INGREDIENT_TABLE";
    public static final int VERSION = 1;
    public static final String TABLE_NAME = "ingredient_table";

    public static final String KEY_ID = "ID";
    public static final String COL_NAME = "Name";
    public static final String COL_AMOUNT = "AMOUNT";


    public TableIngredient (Context context) {
        super(context, DB_NAME, null, VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
    String createQuery = "CREATE TABLE " + TABLE_NAME
            + "(" + KEY_ID + " INTEGER PRIMARY KEY, "
            + COL_NAME + " TEXT NOT NULL, "
            + COL_AMOUNT + " INTEGER DEFAULT NULL)";
    db.execSQL(createQuery);
    }

    public boolean checkRow(Ingredient ingredient){
        SQLiteDatabase db = this.getReadableDatabase();
        Cursor c = db.query(TABLE_NAME,
            new String[]{KEY_ID, COL_NAME, COL_AMOUUNT},
            KEY_ID + " =? AND " + COL_NAME + " =? AND " + COL_AMOUNT + " =?" ,
            new String[]{String.valueOf(ingredient)},
            null, null, null, null);

        ContentValues values = new ContentValues();
        values.put(COL_NAME, ingredient.getName());
        values.put(COL_AMOUNT, ingredient.getAmount());

        if (c.moveToFirst()){
            increseIngredient(ingredient);
            return true;
        }
        else {
            long newID = db.insert(TABLE_NAME, null, values);
            db.close();
            getIngredient(newID);
            return false;
        }
    }
}

With this code it always uses the else statement and I do not know why this happens.使用这段代码,它总是使用 else 语句,我不知道为什么会发生这种情况。

I hope someone can help me to create a new row if it not exists and update the row if it exists.我希望有人可以帮助我创建一个不存在的新行,如果存在则更新该行。

With this code it always uses the else statement and I do not know why this happens.使用这段代码,它总是使用 else 语句,我不知道为什么会发生这种情况。

The reason why this happens is that the 4th parameter to the query method is new String[]{String.valueOf(ingredient)}发生这种情况的原因是查询方法的第 4 个参数是new String[]{String.valueOf(ingredient)}

This will resolve to being a value something like Ingredient@1091 do you have an ingredient row that has an ID like that ( rhetorical as that cannot be the case due to the ID column being an alias of the rowid and therefore ONLY integer values can be stored ).这将解析为类似于Ingredient@1091的值,您是否有一个具有类似 ID 的成分行(修辞,因为 ID 列是 rowid 的别名,因此只能是整数值存储)。

The reason that Ingredient@1091 is that the String value of the Ingredient object will be a pointer to the object. Ingredient@1091的原因是 Ingredient 对象的 String 值将是一个指向该对象的指针。

As such no rows will ever be returned.因此,不会返回任何行。

If instead you used new String[]{String.valueOf(ingredient.getId),ingredient.getName,ingredient.getAmount)}如果您改为使用new String[]{String.valueOf(ingredient.getId),ingredient.getName,ingredient.getAmount)}

The 3 values would (should), be the correct values (assuming that the ID is stored correctly in the Ingredient).这 3 个值将(应该)是正确的值(假设 ID 正确存储在成分中)。

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