std :: string的转换运算符无法与赋值一起使用

Question

I am using a proxy type to defer the work until the result is assigned to a variable, it works by using conversion operators on the proxy type. When adding an conversion operator overload for std::string , it works for string construction from proxy, but fails to compile for assignment, with the following error message:

error: ambiguous overload for 'operator='

While this question is similar to the one at operator T() not used in assignment , solution there is not applicable here since I am also using templated conversion operator.

Below is the snippet:

#include <iostream>
#include <string>

struct Proxy
{
    template < typename T >
    operator T ()
    {
        T res;
        std::cerr << "Converting to T: " << typeid( T ).name() << "\n";
        return res;
    }

    operator std::string ()
    {
        std::string res;
        std::cerr << "Converting to string\n";
        return res;
    }
};


int main()
{
    struct Foo {};

    Proxy proxy;

    bool b = proxy; // Construct, works
    b = proxy;      // Assignment, works

    Foo f = proxy; // Construct, works
    f = proxy;     // Assignment, works

    std::string s = proxy; // Construct, works
    s = proxy;             // Assignment, this line fails to compile <<<<<

    return 0;
};

How can this proxy be made to work with the string assignment?

Answer 1

How can this proxy be made to work with the string assignment?

The compiler is unable to tell what conversion you want. It could be anything that can be used to construct an std::string - char , char * , std::string , ...

So the solution is to tell the compiler what you want. Make an explicit operator call:

s = proxy.operator std::string();