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如何检查命令行中的输入是C中的整数?

[英]How to check input in command line is integer in C?

I want the code to check input in command line is integer.我希望在命令行中检查输入的代码是整数。 ie 10b is not valid.即 10b 无效。 I tried isdigit() but is not working?我试过 isdigit() 但不起作用? Thanks in advance.提前致谢。

#include <cs50.h>
#include <stdio.h>
#include <ctype.h>

int main(int argc, string argv[])
{
   if (argc == 2)
   {
       int key = atoi(argv[1]);

       if (isdigit(key))
       {
          printf("Success\n\%i\n", key);
          exit(0);
       }

    }
  printf("Usage: ./caesar key\n");
  return 1;
}

Function isDigit checks if a single character is a digit, ie in the range between '0'..'9' .函数isDigit检查单个字符是否为数字,即在'0'..'9'之间的范围内。 To check if a string is a number, I'd suggest to use function strtol .要检查字符串是否为数字,我建议使用函数strtol

long strtol(const char *str, char **str_end, int base ) converts a string str to an integral number and also sets the pointer str_end to the first character that took not part in the conversion any more. long strtol(const char *str, char **str_end, int base )将字符串str转换为整数,并将指针str_end设置为不再参与转换的第一个字符。 If you require that no characters must follow your number, then str_end must point to the string's end, ie to string termination character '\\0' :如果您要求数字str_end不能有任何字符,则str_end必须指向字符串的结尾,即字符串终止字符'\\0'

#include <stdio.h>
#include <stdlib.h>

int isNumber(const char* str) {

    if (!str || *str=='\0') {  // NULL str or empty str: not a number
        return 0;
    }

    char* endOfNum;
    strtol(str,&endOfNum,10);

    if (*endOfNum == '\0') { // string is at its end; everything in it was a valid part of the number
        return 1;
    } else {
        return 0;  // something that is not part of a number followed.
    }

}

int main() {
    const char* vals[] = {
        "10b",
        "-123",
        "134 ",
        "   345",
        "",
        NULL
    };

    for (int i=0; vals[i]; i++) {
        printf("testing '%s': %d\n", vals[i], isNumber(vals[i]));
    }
}

Output:输出:

testing '10b': 0
testing '-123': 1
testing '134 ': 0
testing '   345': 1
testing '': 0

Adapt the meaning of corner cases like empty strings or NULL-strings to your needs.根据您的需要调整特殊情况(如空字符串或 NULL 字符串)的含义。

My first thought would be to use something like:我的第一个想法是使用类似的东西:

int inputvalue = 0;
if (sscanf(argv[i], "%d", &inputvalue) == 1)
{
    // it's ok....
}
else
{
    // not an integer!
}

or something like that.或类似的东西。 See http://www.cplusplus.com/reference/cstdio/sscanf/http://www.cplusplus.com/reference/cstdio/sscanf/

The isdigit function checks whether a single character represents a single digit. isdigit函数检查单个字符是否代表单个数字。 (numbers − 0 1 2 3 4 5 6 7 8 9). (数字 - 0 1 2 3 4 5 6 7 8 9)。

In order to check if a string is an integer you could use a function like that.为了检查字符串是否为整数,您可以使用这样的函数。 It will它会

bool isNumber(char number[])
{
    int i = 0;
    // only if you need to handle negative numbers 
    if (number[0] == '-')
        i = 1;
    for (; number[i] != 0; i++)
    {
        if (!isdigit(number[i]))
            return false;
    }
    return true;
}

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