[英]How to Create a Nested JSON using Python
I already read Create nested JSON from csv, but it didn't help in my case. 我已经阅读了从csv创建嵌套JSON的内容,但对我而言没有帮助。
I would like to create a json from an excel spreadsheet using python. 我想使用python从Excel电子表格创建一个json。 the code below generates a dic then a json, however i would like to revise the code further so that i can get the following json.
下面的代码生成一个dic然后是一个json,但是我想进一步修改代码,以便获得以下json。 I have had no luck so far.
到目前为止,我还没有运气。
Desired outcome : 预期结果 :
{"items": { "AMS Upgrade": [ {"Total": "30667"}, {"% Complete to end": "100%"}, {"value claimed": "25799"} ], "BMS works": [ {"Total": "35722"}, {"% Complete to end": "10%"}, {"value claimed": "3572"} ] }}
{“ items”:{“ AMS Upgrade”:[{“ Total”:“ 30667”},{“%Complete to end”:“ 100%”},{“ value value”:“ 25799”}],“ BMS作品”:[{“总计”:“ 35722”},{“%完成至结束”:“ 10%”},{“价值主张”:“ 3572”}]}}
Current outcome : 当前结果 :
{"line items": {"AMS Upgrade": "30667", "BMS Modification": "35722"}}
{“订单项”:{“ AMS升级”:“ 30667”,“ BMS修改”:“ 35722”}}
Current code: 当前代码:
book = xlrd.open_workbook("Example - supporting doc.xls")
first_sheet = book.sheet_by_index(-1)
nested_dict = {}
nested_dict["line items"] = {}
for i in range(21,175):
Line_items = first_sheet.row_slice(rowx=i, start_colx=2, end_colx=8)
if str(Line_items[0].value) and str(Line_items[1].value):
if not Line_items[5].value ==0 :
print str(Line_items[0].value)
print str(Line_items[5].value)
nested_dict["line items"].update({str(Line_items[0].value) : str(Line_items[1].value)})
print nested_dict
print json.dumps(nested_dict)
book = xlrd.open_workbook("Example - supporting doc.xls")
first_sheet = book.sheet_by_index(-1)
nested_dict = {}
nested_dict["line items"] = {}
col_names = {1: "Total", 2: "% Complete to end", 5: "value claimed"}
for i in range(21,175):
Line_items = first_sheet.row_slice(rowx=i, start_colx=2, end_colx=8)
if str(Line_items[0].value) and str(Line_items[1].value):
if not Line_items[5].value ==0 :
inner_list = []
for j in [1, 2, 5]:
inner_list.append({col_names[j]: Line_items[j].value})
nested_dict["line items"].update({str(Line_items[0].value) : inner_list})
print(nested_dict)
print(json.dumps(nested_dict))
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