从jenkinsfile调用python脚本会输出标准输出，但不会返回返回值

Question

I'm using the following py script and triggering it with the following groovy script. The triggering itself is done by groovy b.jenkinsfile :

a.py - Python 2.7

import sys

def main(x):
    print x
    return 2

if __name__ == '__main__':
    main(sys.argv[1:])

b.jenkinsfile - Groovy

def cmd = ["python", "a.py", "arg"]
def func = cmd.execute()
func.waitForOrKill(10000)
println func.text
func.dump()
println func

The output I get is ["arg"] which is about what I expected (actually expected it without the [], but that's beside the point).

I can't seem to get the actual return value of the object. why is text / dump / func itself won't give the return value?

tried also return main(sys.argv[1:]) instead of plain calling to main , but that supressed my print x for some reason...

Answer 1

to get exit value use func.exitValue() .

the method execute() returns Process object instance that extended by groovy with additional methods

the [] brackets you have because in python you are accessing the sublist of arguments starting from first one:

sys.argv[1:]

as soon as this accessor returns a list (even with only one element) - it wrapped with [] on output.

if you want to get just one element use

sys.argv[1]

Answer 2

You are expecting the value returned by the function main() to be passed to the OS as a return code.

It doesn't. You need to explicitly pass it to the OS.

rc = main(sys.argv[1:])
sys.exit(rc)

And you got ["arg"] because sys.argv[1:] asks for a slice (that is, a sublist) of sys.argv . If you just want one element, use sys.argv[1] which selects element 1.