从java程序执行bat文件时找不到文件

Question

I have this code that used to work, but now I´m getting that the program can´t find the file but the file is there.

This is my code. My project is in C:\\Users\\user\\git\\project and the apps folder is C:\\Users\\user\\git\\apps\\folder .

        ProcessBuilder pb = null;
       pb = new ProcessBuilder("myApp.bat");                         
        pb.directory(newFile("C:\Users\user\git\project\..\apps\folder"));
        File log = new File("log");
        pb.redirectErrorStream(true);
        pb.redirectOutput(Redirect.appendTo(log));

        Process p = pb.start();
      assert pb.redirectInput() == Redirect.PIPE;
      assert pb.redirectOutput().file() == log;
      assert p.getInputStream().read() == -1;

And I´m getting Cannot run program "myApp.bat" (in directory "C:\\Users\\user\\git\\project\\..\\apps\\folder"): CreateProcess error=2, Can´t find file

Answer 1

You are specifying an incorrect folder path for your bat file.

You are specifying

C:\\Users\\user\\git\\project\\..\\apps\\folder

but you are saying that the correct folder is C:\\Users\\user\\git\\project\\..\\apps\\folder .

Change the line

pb.directory(newFile("C:\\Users\\user\\git\\project\\..\\apps\\folder"));

to

pb.directory(newFile("C:\\Users\\user\\git\\project\\apps\\folder"));

The .. refers to change in directory. So your actual path becomes C:\\Users\\user\\git\\apps\\folder instead of C:\\Users\\user\\git\\project\\apps\\folder