[英]Problem with reading lines in TXT File, for line in
I have a problem which don't let me to make a Login System.我有一个问题,不允许我制作登录系统。 What I want to do here is Open the TXT file, and search for Username and Password in one line.
我想在这里做的是打开TXT文件,并在一行中搜索用户名和密码。 If the password and Username is in the one Line, the login is successful, we can continue.
如果密码和用户名在一行,则登录成功,我们可以继续。 My code:
我的代码:
elif "l" in Register_Login or "L" in Register_Login:
check = True
while open(Database, mode = 'r', encoding = 'utf-8') as f:
Vardas = input("Please enter your Username!\n")
Password = getpass.getpass("Please enter your Password!\n")
for line in f:
if("Vardas : " + Vardas + " Password : " + Password + " ") == line.strip():
print("You're logged in")
check = False
break;
else:
print("Wrong Combination!")
continue;
EDIT** After editing some code, I get another error.编辑** 编辑一些代码后,我又收到一个错误。
elif "l" in Register_Login or "L" in Register_Login:
check = True
with open('Registruoti.txt', mode = 'r', encoding = 'utf-8') as f:
Vardas = input("Please enter your Username!\n")
Password = getpass.getpass("Please enter your Password!\n")
for line in f:
if("Vardas : " + Vardas + " Password : " + Password + " ") == line.strip():
print("You're logged in")
check = False
break;
else:
print("Wrong Combination!")
continue;
It is not supposed to work, the correct way to use a context manager is by using with
keyword, not while
.它不应该工作,使用上下文管理器的正确方法是使用
with
关键字, while
不是while
。 Also preserve the correct indentation after using a context manager.使用上下文管理器后还要保留正确的缩进。
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