SQL编号比较和汇总

Question

and using snowflake database. There is a task I'm trying to solve but don't know where to start. I want to do calculate the percentage of BIDS higher than/lower than/equal to PRICE and the accepted price. There are thousands of IDs, below is one of them. The example data has 2 bids equal to price(180), one bid higher than price (200), and one bid lower than price (100). The accepted price's difference in percentage with price (100/180 = 0.55)

ID,     PRICE,ID,   BIDS,ACCEPTED
2134323,180,2134323,200,FALSE
2134323,180,2134323,180,FALSE
2134323,180,2134323,180,FALSE
2134323,180,2134323,100,TRUE

Expected output:

ID,     PRICE ACCEPTED HIGHER LOWER EQUAL
2134323 180    0.55      0.25   0.25  0.5

Any suggestion how to complete this?

Answer 1

Conditional aggregation should work:

select id, price
       max(case when accepted = 'TRUE' then bids end) / price as accepted,
       avg(case when bids > price then 1.0 else 0 end) as higher,
       avg(case when bids < price then 1.0 else 0 end) as lower,
       avg(case when bids = price then 1.0 else 0 end) as equal
from t
group by id, price;